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Svetach [21]
3 years ago
6

An insulated cup contains 66.0g of water at 22.00oC. A 28.50g sample of metal at 95.25oC is added. The final temperature of the

water and metal is 27.84oC. What is the specific heat of the metal
Chemistry
1 answer:
Vsevolod [243]3 years ago
7 0

Answer:

Specific heat of metal of the metal is 0.8394J/g°C

Explanation:

The heat the water gain is the same losing for the metal. The equation is:

m(Metal)*ΔT(Metal)*S(Metal) = m(Water)*ΔT(Water)*S(Water)

<em>Where m is mass: 66.0g water and 28.5g Metal</em>

<em>ΔT is change in temperature: (95.25°C-27.84°C) = 67.41°C for the metal and (27.84°C - 22.00°C) = 5.84°C for the water</em>

<em>And S is specific heat of water (4.184J/g°C) and the metal</em>

<em />

Replacing:

28.5g*67.41°C*S(Metal) = 66.0g*5.84°C*4.184J/g°C

S(Metal) = 0.8394J/g°C

<h3>Specific heat of metal of the metal is 0.8394J/g°C</h3>

<em />

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A solution of LiCl in water is 20.0 wt% LiCl. What is the mole fraction of LiCl?0.09600.4720.1064.44
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mole fraction of LiCl = 0.096

Explanation:

Weight percentage -

weight percentage of A is given as , the weight of the substance A by weight of the total solution multiplied by 100 .  

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weight % A = weight of A / weight of solution * 100

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20.0 wt% LiCl

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Since ,

Moles is denoted by given mass divided by the molecular mass ,

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m = molecular mass .

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Mole fraction -

It is the ratio of the moles of one of the component of the solution by the mole of the solution .

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mole fraction of LiCl = moles of LiCl / total moles  = 0.472 mol / 4.92

mole fraction of LiCl = 0.096

3 0
3 years ago
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