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BaLLatris [955]
3 years ago
5

The trade route that connected India to markets in Europe and the Arabian

Chemistry
2 answers:
Aloiza [94]3 years ago
5 0

Answer:

It is NOT B (Silk Road trade network), I repeat NOT B, but I think it could be A (Indian Ocean trade network)

Explanation:

I took the quiz and chose B (Silk Road trade network) and it was INCORRECT. As for A (Indian Ocean trade network), I looked back at the lesson and it doesn't mention <em>anything </em>about D (the Songhai trade network), which rules that one out, so now it's between A and C. I don't think it's C (trans-Saharan trade network) because although it was near the Arabian Peninsula, it said that it trades with civilizations in the Saharan Desert and people who live near the Mediterranean Sea. It also said nothing about trading with Europe (Roman Empire at that time) along the trans-Saharan trade network. So that's why I'm thinking it could be the Indian Ocean trade network because 1. it's the only one that makes sense after we've ruled out the others 2. It traded with the Arabian Peninsula, and since it traveled over water, I'm thinking it could've gotten to Europe. Then again I could be wrong, but keep these in mind while answering.

Elan Coil [88]3 years ago
5 0

Answer:

A

Explanation:

Took the test and got it right

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Answer:

D. Na₃X

Explanation:

We have the neutral compound Ba₃(X)₂. <em>The total charge (zero) is equal to the sum of the charges of the ions times the number of ions in the molecule</em>.

3 × qBa + 2 × qX = 0

3 × (+2) + 2 × qX = 0

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If we have the cation Na⁺ and X³⁻, a neutral molecule would require 3 Na⁺ and 1 X³⁻. The resulting compound is Na₃X.

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The equation for the enthalpy change of the above reaction is:

\Delta H^o_{rxn}=[(8\times \Delta H^o_f_{CO_2(g)})+(10\times \Delta H^o_f_{H_2O(g)})]-[(1\times \Delta H^o_f_{C_4H_{10}(g)})+(4\times \Delta H^o_f_{O_2(g)})]

We are given:

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Putting values in above equation, we get:

\Delta H^o_{rxn}=[(8\times -393.5)+(10\times -241.82)]-[(2\times -125.6)+(4\times 0)]\\\\\Delta H^o_{rxn}=-5315kJ

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