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BaLLatris [955]
3 years ago
5

The trade route that connected India to markets in Europe and the Arabian

Chemistry
2 answers:
Aloiza [94]3 years ago
5 0

Answer:

It is NOT B (Silk Road trade network), I repeat NOT B, but I think it could be A (Indian Ocean trade network)

Explanation:

I took the quiz and chose B (Silk Road trade network) and it was INCORRECT. As for A (Indian Ocean trade network), I looked back at the lesson and it doesn't mention <em>anything </em>about D (the Songhai trade network), which rules that one out, so now it's between A and C. I don't think it's C (trans-Saharan trade network) because although it was near the Arabian Peninsula, it said that it trades with civilizations in the Saharan Desert and people who live near the Mediterranean Sea. It also said nothing about trading with Europe (Roman Empire at that time) along the trans-Saharan trade network. So that's why I'm thinking it could be the Indian Ocean trade network because 1. it's the only one that makes sense after we've ruled out the others 2. It traded with the Arabian Peninsula, and since it traveled over water, I'm thinking it could've gotten to Europe. Then again I could be wrong, but keep these in mind while answering.

Elan Coil [88]3 years ago
5 0

Answer:

A

Explanation:

Took the test and got it right

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What is the equilibrium constant of pure water at 25C?
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4 years ago
How many grams of silver bromide are produced when 505 grams of cobalt (III) bromide reacts completely in the following equation
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Explanation:
Given data:
Mass of cobalt(III) nitrate = 206 g
Mass of silver bromide produced = ?
Solution:
Chemical equation:
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7 0
3 years ago
Zinc is used as a coating for steel to protect the steel from environmental corrosion. If a piece of steel is submerged in an el
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Answer:

A) 3.17 g of Zn

Explanation:

Let's consider the reduction of Zn(II) that occurs in an electrolysis bath.

Zn⁺²(aq) + 2e⁻ → Zn(s)

We can establish the following relations:

  • 1 min = 60 s
  • 1 A = 1 C/s
  • The charge of 1 mole of electrons is 96,468 C (Faraday's constant).
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The mass of Zn deposited under these conditions is:

24min \times \frac{60s}{1min} \times \frac{6.5C}{s} \times \frac{1mol\ e^{-} }{96,468C} \times \frac{1molZn}{2mol\ e^{-}}  \times \frac{65.38g}{1molZn} = 3.17 g

3 0
3 years ago
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