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3 years ago

PLZ HELP MEE!!!!!!!!!!

Mathematics

2 answers:

Lena [83]3 years ago

8 0

5dhkwasgnbfrrfgfggff

snow_tiger [21]3 years ago

4 0

Answer:

y=7(x-5)+3

Step-by-step explanation:

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Cross multiplication

denis23 [38]

Answer:

7. 5/6 8. 3/12

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

1 + 3 - (8 * 334 * 123) = x x = ?

il63 [147K]

Answer:

if, 1 + 3 - (8 * 334 * 123) = x

then, x = -328652

8 0

3 years ago

Here is a triangular pyramid and its net.

galben [10]

Answer:

a) Area of the base of the pyramid = $15.6\ mm^{2}$

b) Area of one lateral face = $24\ mm^{2}$

c) Lateral Surface Area = $72\ mm^{2}$

d) Total Surface Area = $87.6\ mm^{2}$

Step-by-step explanation:

We are given the following dimensions of the triangular pyramid:

Side of triangular base = 6mm

Height of triangular base = 5.2mm

Base of lateral face (triangular) = 6mm

Height of lateral face (triangular) = 8mm

a) To find Area of base of pyramid:

We know that it is a triangular pyramid and the base is a equilateral triangle. $\text{Area of triangle = } \dfrac{1}{2} \times \text{Base} \times \text{Height} ..... (1)\\$

${\Rightarrow \text{Area of pyramid's base = }\dfrac{1}{2} \times 6 \times 5.2\\\Rightarrow 15.6\ mm^{2}$

b) To find area of one lateral surface:

Base = 6mm

Height = 8mm

Using equation (1) to find the area:

$\Rightarrow \dfrac{1}{2} \times 8 \times 6\\\Rightarrow 24\ mm^{2}$

c) To find the lateral surface area:

We know that there are 3 lateral surfaces with equal height and equal base.

Hence, their areas will also be same. So,

$\text{Lateral Surface Area = }3 \times \text{ Area of one lateral surface}\\\Rightarrow 3 \times 24 = 72 mm^{2}$

d) To find total surface area:

Total Surface area of the given triangular pyramid will be equal to Lateral Surface Area + Area of base

$\Rightarrow 72 + 15.6 \\\Rightarrow 87.6\ mm^{2}$

Hence,

a) Area of the base of the pyramid = $15.6\ mm^{2}$

b) Area of one lateral face = $24\ mm^{2}$

c) Lateral Surface Area = $72\ mm^{2}$

d) Total Surface Area = $87.6\ mm^{2}$

8 0

3 years ago

Prove that Tan x + Cos x = 1 /Sin x .Cos x

Anit [1.1K]

Answer:

tanx + cotx = $\frac{1}{sinxcosx}$

Step-by-step explanation:

Explanation

Take R.H.S = $\frac{1}{sinxcosx}$

= $\frac{sin^{2}x+cos^{2}x }{sinxcosx}$

= $\frac{sin^{2}x }{sinx cosx} + \frac{cos^{2} x}{sinxcosx}$

= $\frac{sinx}{cosx} + \frac{cosx}{sinx}$

= tanx + cotx

tanx + cotx = $\frac{1}{sinxcosx}$

5 0

3 years ago

What’s the correct answer for this ?

pickupchik [31]

Answer:

Blank 1) 150

Blank 2) (3)²

3) (4)²

4) (x+3)²

5) (y-3)²

6) (x+3)²+(y-3)² = 100

6 0

3 years ago