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3 years ago

A father is 28 years older than his daughter. In six years' time, he will be three times her age. Find their present ages.

Mathematics

1 answer:

love history [14]3 years ago

8 0

Answer:

8 and 36

Step-by-step explanation:

let the daughter's age be x then father is x + 28

In 6 years their ages are

x + 6 and x + 28 + 6 = x + 34

Father is 3 times her age , then equation is

x + 34 = 3(x + 6) ← distribute

x + 34 = 3x + 18 ( subtract x from both sides )

34 = 2x + 18 ( subtract 18 from both sides )

16 = 2x ( divide both sides by 2 )

8 = x

Daughter's age is 8 and father's age is 8 + 28 = 36

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