All categories

3 years ago

What is the solution of the equation n/10 = 7?n= ____

Mathematics

2 answers:

Nadya [2.5K]3 years ago

5 0

Hi there!

»»————-　★　————-««

I believe your answer is:

$n=70$

»»————-　★　————-««

Here’s why:

We will use inverse operations to solve for 'n'.

⸻⸻⸻⸻

$\boxed{\text{Solving for 'n'...}}\\\\\frac{n}{10}=7\\---------\\\rightarrow(\frac{n}{10})10=7(10)\\\\\rightarrow\boxed{n=70}$

⸻⸻⸻⸻

»»————-　★　————-««

Hope this helps you. I apologize if it’s incorrect.

ozzi3 years ago

3 0

Answer:

n = 70

Step-by-step explanation:

n/10 = 7

Multiply each side by 10

n/10 *10 = 7*10

n = 70

You might be interested in

What is the first term of the geometric sequence presented in the table below?

Leto [7]

Fron the table given:

A3 = 112,
A8 = - 3,584

An = A1 *r ^ (n-1)

=> A3 = A1 (r^2) = 112

A8 = A1(r^7) = - 3,584

=> - 3584 / 112 = (r^7) / (r^2)

=> (r^5) = - 32

=> r = - 2

=> A1 (- 2)^2 = 112

=> A1 = 112 / 4 = 28

Answer: a1 = 28

8 0

3 years ago

Please answer i need help!!!!! WILL GIVE BRAINLIEST!!!!!

sp2606 [1]

1. D. 4 x 4 x 4 x 4 x 4

2. B. 6³ (6 x 6 x 6 = 216)

3. D. (8², 100^1, 11², 5³)

4. D. Sum (There's No addition anywhere in that equation)

5. C. h (Because there's no number before the h²)

6. C. 24

7. C. Raise 9 to the 2nd power (Follow PEMDAS, after doing the parentheses, you need to do the exponents, and C. you need to the exponents)

8. A. 4xy

9. C. 18 (I followed PEMDAS, and received the answer 18)

10. B. 49

----------------------------------------------------------------------------------------------------------------

I hope this helps, and Happy Holidays! :)

4 0

3 years ago

Decrease 40 by 15% please explain how you got your answer too :)

Anit [1.1K]

So 10 % of 40 is 4
5% of 40 is 2
so 15% is 6
then you have to do 40-6
and then you get the answer of 34

8 0

3 years ago

(7x7x7x7x7x7x7)-3x-3x-3

Anna71 [15]

Answer:

823516

Step-by-step explanation:

hope this helps

8 0

3 years ago

Read 2 more answers

Evaluate the integral, show all steps please!

Aloiza [94]

Answer:

$\displaystyle \int \dfrac{1}{(9-x^2)^{\frac{3}{2}}}\:\:\text{d}x=\dfrac{x}{9\sqrt{9-x^2}} +\text{C}$

Step-by-step explanation:

Fundamental Theorem of Calculus

$\displaystyle \int \text{f}(x)\:\text{d}x=\text{F}(x)+\text{C} \iff \text{f}(x)=\dfrac{\text{d}}{\text{d}x}(\text{F}(x))$

If differentiating takes you from one function to another, then integrating the second function will take you back to the first with a constant of integration.

Given indefinite integral:

$\displaystyle \int \dfrac{1}{(9-x^2)^{\frac{3}{2}}}\:\:\text{d}x$

Rewrite 9 as 3² and rewrite the 3/2 exponent as square root to the power of 3:

$\implies \displaystyle \int \dfrac{1}{\left(\sqrt{3^2-x^2}\right)^3}\:\:\text{d}x$

Integration by substitution

$\boxed{\textsf{For }\sqrt{a^2-x^2} \textsf{ use the substitution }x=a \sin \theta}$

$\textsf{Let }x=3 \sin \theta$

$\begin{aligned}\implies \sqrt{3^2-x^2} & =\sqrt{3^2-(3 \sin \theta)^2}\\ & = \sqrt{9-9 \sin^2 \theta}\\ & = \sqrt{9(1-\sin^2 \theta)}\\ & = \sqrt{9 \cos^2 \theta}\\ & = 3 \cos \theta\end{aligned}$

Find the derivative of x and rewrite it so that dx is on its own:

$\implies \dfrac{\text{d}x}{\text{d}\theta}=3 \cos \theta$

$\implies \text{d}x=3 \cos \theta\:\:\text{d}\theta$

Substitute everything into the original integral:

$\begin{aligned}\displaystyle \int \dfrac{1}{(9-x^2)^{\frac{3}{2}}}\:\:\text{d}x & = \int \dfrac{1}{\left(\sqrt{3^2-x^2}\right)^3}\:\:\text{d}x\\\\& = \int \dfrac{1}{\left(3 \cos \theta\right)^3}\:\:3 \cos \theta\:\:\text{d}\theta \\\\ & = \int \dfrac{1}{\left(3 \cos \theta\right)^2}\:\:\text{d}\theta \\\\ & = \int \dfrac{1}{9 \cos^2 \theta} \:\: \text{d}\theta\end{aligned}$

Take out the constant:

$\implies \displaystyle \dfrac{1}{9} \int \dfrac{1}{\cos^2 \theta}\:\:\text{d}\theta$

$\textsf{Use the trigonometric identity}: \quad\sec^2 \theta=\dfrac{1}{\cos^2 \theta}$

$\implies \displaystyle \dfrac{1}{9} \int \sec^2 \theta\:\:\text{d}\theta$

$\boxed{\begin{minipage}{5 cm}\underline{Integrating $\sec^2 kx$}\\\\$\displaystyle \int \sec^2 kx\:\text{d}x=\dfrac{1}{k} \tan kx\:\:(+\text{C})$\end{minipage}}$