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2 years ago

Chose the equation that has solutions (5,7) and (8,13)

Mathematics

1 answer:

KIM [24]2 years ago

7 0

The last one .........

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Question is worth 25 points what is 15 squared?

makkiz [27]

The answer is 225
15•15=225

7 0

3 years ago

The average monthly cell phone bill was reported to be $50.07 by the U.S. Wireless Industry. Random Sampling of a large cell pho

zalisa [80]

Answer:

The null and alternative hypotheses are:

$H_{0}:\mu= 50.07$

$H_{a}:\mu>50.07$

Under the null hypothesis, the test statistic is:

$t=\frac{\bar{x}-\mu}{\frac{s}{\sqrt{n}} }$

Where:

$\bar{x} = 52.86$ is the sample mean

$s=7.0132$ is the sample standard deviation

$n=10$ is the sample size

$\therefore t=\frac{52.86-50.07}{\frac{7.0132}{\sqrt{10}} }$

$=1.26$

Now, the right tailed t critical value at 0.05 significance level for df = n-1 = 10-1 = 9 is:

$t_{critical}=1.833$

Since the t statistic is less than the t critical value at 0.05 significance level, therefore,we fail to reject the null hypothesis and conclude that there is not sufficient evidence to support the claim that the average phone bill has increased.

4 0

2 years ago

brazil exports the most coffee in the world it cost approximately $2.55 to produce a pound of coffee.Also the us charges 20% tar

exis [7]

Answer:

I believe it is 3.1875.

Step-by-step explanation:

25% of 2.55 is 0.6375.

2.55 + 0.6375 = 3.1875.

3 0

2 years ago

After eating at a restaurant, Mr. Jackson’s bill before tax is $42.50 The sales tax rate is 8%. Mr. Jackson decides to leave a 2

USPshnik [31]

Answer:

$3.40

Step-by-step explanation:

Look at image above...

6 0

2 years ago

It is believed that the average amount of money spent per U.S. household per week on food is about $98, with standard deviation

Makovka662 [10]

Answer:

Test statistic = 2

P-value = 0.0227

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = $98

Sample mean, $\bar{x}$ = $100

Sample size, n = 100

Population standard deviation, σ = $10

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 98\text{ dollars}\\H_A: \mu > 98\text{ dollars}$

Formula:

$z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }$

Putting all the values, we have

$z_{stat} = \displaystyle\frac{100 - 98}{\frac{10}{\sqrt{100}} } = 2$

Now, we can calculate the p-value from the normal table

P-value = 0.0227

6 0

3 years ago