Answer:
Step-by-step explanation:
When you have exponents above a like term and they are being multiplied together, you add them.
For example:
So let's group like terms in the numerator:
We can add terms like in the example.
Let's rearrange the denominator.
Now we have:
Cancel like terms
4/8 = 1/2
= 1 So it cancels
= s Since s is raised to the -1 it goes on top and becomes s.
Now we combine everything back together:
Answer:
Infinitely Many Solutions
Step-by-step explanation:
Given
Required
Determine the type of solution
From the matrix, we have:
3 non-zero rows and 5 variables (the last column is the result)
When the number of variables is more than the number of non-zero rows, then such system has infinitely many solutions
i.e.
Answer:
Step-by-step explanation:
1.
Simplify the expression by combining like terms. Remember, like terms have the same variable part, to simplify these terms, one performs operations between the coefficients. Please note that a variable with an exponent is not the same as a variable without the exponent. A term with no variable part is referred to as a constant, constants are like terms.
2.
Use a very similar method to solve this problem as used in the first. Please note that all of the rules mentioned in the first problem also apply to this problem; for that matter, the rules mentioned in the first problem generally apply to any pre-algebra problem.
3.
Use the same rules as applied in the first problem. Also, keep the distributive property in mind. In simple terms, the distributive property states the following (). Also note, a term raised to an exponent is equal to the term times itself the number of times the exponent indicates. In the event that the term raised to an exponent is a constant, one can simplify it. Apply these properties here,
4.
The same method used to solve problem (3) can be applied to this problem.