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3 years ago

If P is the incenter of triangle JKL, find the measure of JKP.

Mathematics

1 answer:

ladessa [460]3 years ago

6 0

Answer:

m∠JKP = 31.5°

Step-by-step explanation:

Incenter of a triangle is the point where all the bisectors of interior angles intersect each other.

JN is the angle bisector of ∠KJL.

Therefore, m∠KJN = m∠LJN

(7x - 6) = (5x + 4)

7x - 5x = 6 + 4

2x = 10

x = 5

m∠KJN = (7x - 6)

= 7(5) - 6

= 35 - 6

= 29°

In ΔKJN,

m∠JKN + m∠KNJ + m∠NJK = 180°

m∠JKN + 90° + 29° = 180°

m∠JKN = 180°- 119° = 61°

Since KO is the angle bisector of ∠JKN,

m∠JKP = $\frac{1}{2}(\angle JKN)$

= $\frac{1}{2}(61)$

= 30.5°

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$\large\begin{array}{l}\bullet~~\textsf{2}\mathsf{^{nd}}\textsf{ step: Find the argument }\mathsf{\theta}\textsf{ of z:}\\\\ \mathsf{arg(z)=\theta}\\\\ \textsf{is an angle that satisfies the following conditions:}\\\\ \begin{cases} \mathsf{cos\,\theta=\dfrac{a}{|z|}=\dfrac{a}{\sqrt{a^2+b^2}}}\\\\ \mathsf{sin\,\theta=\dfrac{b}{|z|}=\dfrac{b}{\sqrt{a^2+b^2}}} \end{cases}\qquad\quad-\pi$

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$\large\begin{array}{l}\bullet~~\textsf{3}\mathsf{^{rd}}\textsf{ step: Express z in the trigonometric form:}\\\\ \begin{array}{rcl} \mathsf{z}&\!\!=\!\!&\mathsf{|z|\cdot (cos\,\theta+i\,sin\,\theta)}\\\\ \mathsf{-6+6\sqrt{3}\,i}&\!\!=\!\!&\mathsf{12\cdot \left(cos\, \dfrac{2\pi}{3}+i\,sin\,\dfrac{2\pi}{3}\right)\qquad\quad\checkmark} \end{array} \end{array}$

If you're having problems understanding this answer, try seeing it through your browser: brainly.com/question/2154167

$\large\textsf{I hope it helps.}$

Tags: complex number trigonometric form trig absolute value modulus argument angle

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3 years ago

You are constructing a concrete landing pad for a helicopter. You have 4704 cubic feet of concrete.

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a) We have to calculate the height of the pad.

We know that the volume will be 4704 cubic feet.

We also know that the base of the pad is a square of side length 56 feet.

As the volume is the area of the base times the height, we can find the height by dividing the volume by the base area:

$\begin{gathered} V=A_b\cdot h \\ h=\frac{V}{A_b}=\frac{4704\text{ ft}^3}{(56\text{ ft})^2}=\frac{4704}{3136}\text{ ft}=1.5\text{ ft} \end{gathered}$

The height is 1.5 feet.

b) Now, we have a circular pad of which we know the height (1.5 feet) and the volume (4705 ft³). The area of the base will have to be the same as the are of the square: 3136 ft².

The area of this circular pad can be expressed as πD²/4, so we can calculate the diameter D as:

$\begin{gathered} A=3136 \\ \frac{\pi D^2}{4} \\ D^2=3136*\frac{4}{\pi} \\ D^2=3136*\frac{4}{3.14} \\ D^2=3994.9045 \\ D=\sqrt{3994.9045} \\ D\approx63.21 \end{gathered}$

The diameter is approximately 63.21 feet.

Answer:

a) The pad will be 1.5 feet thick

b) The diameter will be 63.21 feet.

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1 year ago