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UkoKoshka [18]
3 years ago
12

A boat is able to move through still water at 20m/s. It makes a round trip to.a town 3km upstream.If the river flows at 5m/s,the

times required for the round trip.is
Physics
1 answer:
marishachu [46]3 years ago
8 0

Answer:

the answer is 320 seconds :)

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D is the answer  I think (0 w 0 )

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A 62 kg skier is moving at 6.5 m/s on frictionless horizontal snow-covered plateau when she encounters a rough patch 3.50 m long
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Answer:

(A). The work done by friction in crossing the patch is -637.98 J.

(B). The speed of skier is 10.57 m/s.

Explanation:

Given that,

Mass of skier = 62 kg

Speed = 6.5 m/s

Length = 3.50 m

Coefficient kinetic friction = 0.30

Height = 2.5 m

(A) we need to calculate the work done by friction in crossing the patch

Using formula of work done

W=-\mu mg\times l

Put the value into the formula

W=-0.30\times62\times9.8\times3.50

W=-637.98\ J

The work done by friction in crossing the patch is -637.98 J.

(B) we need to calculate the speed of skier

Using conservation of energy

K.E_{i}+U_{i}-W_{friction}=K.E_{f}+U_{f}

\dfrac{1}{2}mv_{1}^2+mgh-\mu mgl=\dfrac{1}{2}mv_{2}^2+U_{f}

Final potential energy is zero

So, \dfrac{1}{2}mv_{1}^2+mgh-\mu mgl=\dfrac{1}{2}mv_{2}^2

\dfrac{1}{2}v_{2}^2=\dfrac{1}{2}v_{1}^2+gh-\mu gl

Put the value into the formula

\dfrac{1}{2}v_{2}^2=\dfrac{1}{2}\times6.5^2+9.8\times2.5+0.30\times9.8\times3.50

v_{2}=\sqrt{2\times55.915}

v_{2}=10.57\ m/s

The speed of skier is 10.57 m/s.

Hence,  (A).The work done by friction in crossing the patch is -637.98 J.

(B).The speed of skier is 10.57 m/s.

6 0
3 years ago
if you wanted to increase the energy of a wave but you had to leave the wavelength the same what might you do ​
Blizzard [7]

Answer:

Increase the amplitude

Explanation:

The energy conveyed by a wave is directly proportional to the square of its amplitude. Thus; E ∝ A²

This means that increasing the amplitude will lead to an increase in the energy.

Now, the amplitude of a wave is the height of a wave from it's highest point known as the peak, to the lowest point on the wave known as the trough whereas wavelength refers to the length of a wave from one peak to the next.

This means that increasing the amplitude has no effect on the wavelength.

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