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solmaris [256]
3 years ago
10

7Which of the following terms describes how glaciers move?

Physics
2 answers:
tatuchka [14]3 years ago
7 0

Answer:

D is the answer  I think (0 w 0 )

Explanation:

ollegr [7]3 years ago
5 0
Your answer should me D
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Trees. Every time the wind blows there is a wave of motion which is movement

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Emboldened by the success of their late night keg pull in Exercise 61 above, our intrepid young scholars have decided to pay hom
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Answer is answer

XD                                ssssss

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3 years ago
A stretched string is observed to have four equal segments in a standing wave driven at a frequency of 480 hz. what driving freq
Korvikt [17]

600Hz is the driving frequency needed to create a standing wave with five equal segments.

To find the answer, we have to know about the fundamental frequency.

<h3>How to find the driving frequency?</h3>
  • The following expression can be used to relate the fundamental frequency to the driving frequency;

                                        f(n) = n * f (1)

where, f(1) denotes the fundamental frequency and the driving frequency f(n).

  • The standing wave has four equal segments, hence with n=4 and f(n)=4, we may calculate the fundamental frequency.

                                          f(4) = 4× f (1)

                                          480 = 4× f(1)

                                         f(1) = 480/4 =120Hz.

So, 120Hz is the fundamental frequency.

  • To determine the driving frequency necessary to create a standing wave with five equally spaced peaks?
  • For, n = 5,

                      f(n) = n 120Hz,

                      f(5) = 5×120Hz=600Hz.

Consequently, 600Hz is the driving frequency needed to create a standing wave with five equal segments.

Learn more about the fundamental frequency here:

brainly.com/question/2288944

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8 0
1 year ago
A pendulum is observed to complete 20 full cycles in 60 seconds. Determine the period and the frequency of the pendulum.
Delvig [45]

i hope i have been useful buddy.

good luck ♥️♥️

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3 years ago
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A stationary 15 kg object is located in a table near the surface of the earth. The coefficient of static friction between the su
madreJ [45]

maximum static friction acting on the object will be

F_s = \mu_s mg

plug in all values

F_s = 0.40 \times 15 \times 9.8 = 58.8 N

So here it means that if applied force is less than or equal to 58.8 N then the object will remain stationary as friction can balance the external force upto this limit of external force

So here it is given that applied force is 20 N

so here object will not move due to this force and it will remain at rest always

due to this applied force

6 0
3 years ago
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