Which one of Newton’s Laws best explains a bottle flip?

Three bullets are fired simultaneously by three guns aimed toward the center of a circle where they mash into a stationary lump.

Effectus [21]

Answer: $2.32\times 10^{-3} kg$

Explanation:

Given

mass of first and second bullet $m_1=m_2=3.90\times 10^{-3} kg$

Velocity of two bullets $v_1=v_2=368 m/s$

velocity of third bullet $v_3=618 m/s$

angles between guns is $120^{\circ}$

Suppose First gun is at $0^{\circ}$ and second is at $120^{\circ}$ and third is at $240^{\circ}$

therefore

conserving momentum in x-direction

$m_1v_1\cos 0+m_2v_2\cos 120+m_3v_3\cos 240=0$

as three bullets club together to become lump

$3.90\times 10^{-3}\times 368+3.90\times 10^{-3}\times 368\times \cos (120)+m_3\times 618\times \cos (240)=0$

$3.90\times 10^{-3}\times 368+3.90\times 10^{-3}\times 368\times (-0.5)+m_3\times 618\times (-0.5)=0$

$0.5\times 3.90\times 10^{-3}\times 368=m_3\times 618\times 0.5$

$m_3=3.90\times 10^{-3}\times \frac{368}{618} kg$

$m_3=2.32\times 10^{-3} kg$

5 0

3 years ago

Science in the study of the natural world through. And.

Lyrx [107]

You need to finish the question

6 0

3 years ago

Gibbons move through the trees by swinging from successive handholds, as we have seen. To increase their speed, gibbons may brin

Sedbober [7]

By bring their legs close to their bodies, they are decreasing the length of the pendulum which help them move more quickly.

A pendulum is nothing but a body suspended from a fixed point so that it can swing back and forth under the influence of gravity.

Here in this case Gibbons are bringing their legs close to their bodies and reducing the length of the pendulum. Since as the length of the pendulum increases the speed of the movement will be reduced. By bringing their legs close to their bodies they are reducing the length and in turn their speed increase and they move quickly.

To learn more about pendulum, visit here

brainly.com/question/14759840

#SPJ4

5 0

2 years ago

A railroad train is traveling at a speed of 26.0 m/s in still air. The frequency of the note emitted by the locomotive whistle i

olga55 [171]

Answer: 0.757m; 0.881m; 432.70Hz; 371.89Hz

Explanation:

Give the following :

Velocity of train (Vt) = 26m/s

Frequency of sound (Fs) = 420Hz

Speed of sound (Vs) = 344m/s

1) wavelength = (Vs - Vt) / Fs

Wavelength = (344 - 26) / 420 = 318/420 = 0.757m

11) Wavelength = (Vs + Vt) / Fs

Wavelength = (344 + 26) / 420 = 370/420 = 0.881m

111) According to the doppler effect :

Fl = [(V + Vl) / (V + Vs)] * fs

Fl = frequency of listener ; fs = frequency of sound source ; V = speed of sound ; Vl = Velocity of listener ; Vs = speed of sound source

Vs = - ve (train moving towards listener)

Fl = [(V + Vl) / (V + Vs)] * fs

Fl = [(344 + 0) / (344 - 26)] * 400

Fl = (344 / 318) * 400 = 432.70Hz

1V) Vs = + ve (train moving away listener)

Fl = [(V + Vl) / (V + Vs)] * fs

Fl = [(344 + 0) / (344 + 26)] * 400

Fl = (344 / 370) * 400 = 371.89Hz

6 0

3 years ago

A 6.0 cm candle is 30.0 cm from a concave mirror that has a focal length

Aneli [31]

Answer:

23 cm from the mirror

Explanation:

6 0

4 years ago