All categories

3 years ago

What is 123^3 x 12345^7 =

Mathematics

2 answers:

maw [93]3 years ago

8 0

Answer:

8.1311691e+34

Step-by-step explanation:

loris [4]3 years ago

6 0

8.131169122891e34 is the final answer

You might be interested in

A boat takes 5 hours to go upstream. It can go 50 miles downstream in the same time. Find the rate of the current in the rate of

natka813 [3]

Answer:

Rate of current is 3 miles per hour and speed of the boat in still water is 7 miles per hour.

Step-by-step explanation:

This question is incomplete; find the complete question here.

A boat travels 20 miles upstream in 5 hours. Going downstream, it can travel 50 miles in the same amount of time. Find the speed of the current and the speed of the boat in still water.

Let the speed boat in the still water = x miles per hour

and the speed (rate) of the current = y miles per hour

Speed of the boat to go upstream (against the current) will be = (x - y)miles per hour

Since boat takes 5 hours downstream to travel 50 miles then from the formula,

$\text{Time}=\frac{\text{Distance}}{\text{Speed}}$

$5=\frac{50}{(x+y)}$

(x + y) = 10 -------(1)

Boat takes 5 hours to travel 50 miles upstream then,

$\text{Time}=\frac{\text{Distance}}{\text{Speed}}$

5 = $\frac{20}{(x-y)}$

x - y = 4 -----(2)

By adding equation (1) and question (2)

(x + y) + (x - y) = 14

2x = 14

x = 7 miles per hour

From equation (1),

7 + y = 10

y = 3 miles per hour

Therefore, Rate of current is 3 miles per hour and speed of the boat in still water is 7 miles per hour.

5 0

3 years ago

Find the point P on the graph of the function y=√x closest to the point (9,0)

Sphinxa [80]

Answer:

$\displaystyle \frac{17}{2}$ .

Step-by-step explanation:

Let the $x$ -coordinate of $P$ be $t$ . For $P\!$ to be on the graph of the function $y = \sqrt{x}$ , the $y$ -coordinate of $\! P$ would need to be $\sqrt{t}$ . Therefore, the coordinate of $P \!$ would be $\left(t,\, \sqrt{t}\right)$ .

The Euclidean Distance between $\left(t,\, \sqrt{t}\right)$ and $(9,\, 0)$ is:

$\begin{aligned} & d\left(\left(t,\, \sqrt{t}\right),\, (9,\, 0)\right) \\ &= \sqrt{(t - 9)^2 +\left(\sqrt{t}\right)^{2}} \\ &= \sqrt{t^2 - 18\, t + 81 + t} \\ &= \sqrt{t^2 - 17 \, t + 81}\end{aligned}$ .

The goal is to find the a $t$ that minimizes this distance. However, $\sqrt{t^2 - 17 \, t + 81}$ is non-negative for all real $t\!$ . Hence, the $\! t$ that minimizes the square of this expression, $\left(t^2 - 17 \, t + 81\right)$ , would also minimize $\sqrt{t^2 - 17 \, t + 81}\!$ .

Differentiate $\left(t^2 - 17 \, t + 81\right)$ with respect to $t$ :

$\displaystyle \frac{d}{dt}\left[t^2 - 17 \, t + 81\right] = 2\, t - 17$ .

$\displaystyle \frac{d^{2}}{dt^{2}}\left[t^2 - 17 \, t + 81\right] = 2$ .

Set the first derivative, $(2\, t - 17)$ , to $0$ and solve for $t$ :

$2\, t - 17 = 0$ .

$\displaystyle t = \frac{17}{2}$ .

Notice that the second derivative is greater than $0$ for this $t$ . Hence, $\displaystyle t = \frac{17}{2}$ would indeed minimize $\left(t^2 - 17 \, t + 81\right)$ . This $t\!$ value would also minimize $\sqrt{t^2 - 17 \, t + 81}\!$ , the distance between $P$ $\left(t,\, \sqrt{t}\right)$ and $(9,\, 0)$ .

Therefore, the point $P$ would be closest to $(9,\, 0)$ when the $x$ -coordinate of $P\!$ is $\displaystyle \frac{17}{2}$ .

8 0

3 years ago

ellie must mix 6 tablespoons of plant food for every 2 gallons of water. If she has 6 gallons of water, how muck plant food shou

mel-nik [20]

Answer:

Step-by-step explanation:

she need 18 tablespoons of plant food for 6 gallons of water:)

8 0

3 years ago

Solve 2/3 = x/18 SOMEONE PLS HELP

Mademuasel [1]

Answer:

x = 12

Step-by-step explanation:

what you have to do is cross multiply::

3x = 36

and then single the x out

x = 12

4 0

3 years ago

158, 155,152,...<br><br> Find the 34th term.

NikAS [45]

Answer:

Step-by-step explanation:

the numbers are decreasing by 3 and 3 times 34 is 102

152- 102= 50

lmk if im wrong so i can fix it

EDIT: Its wrong dont use that answer lol

8 0

3 years ago