Answer:
13
Step-by-step explanation:
Answer:
13.5
Step-by-step explanation:
213.21/15.8 ---> ((213.21)100)/((15.8)100)
21321/1580 = 13 R 781.
781/1580 = 0.49~~~
We only need to be concerned about the tenth and hundredth place digits.
The decimal tells us that it rounds up from 4, so it's 5.
Thus, the answers 13+0.5, which is 13.5
A function is a rule that assigns exactly one output to a given input. The input is taken from a set called the domain, and the corresponding output belongs to a set called the range.
1. In this exercise, we're calling the pool of patients 1-8 the domain, and the pool of nurses A-D the range. The given table describes a function because any patient is assigned to only one nurse.
2. This wouldn't be a function if at least one patient was assigned to more than one nurse. If this were to happen in practice, the patient could be, say, given the same dose of some medicine twice if the nurses aren't careful.
3. Making the nurse pool the domain and the patient pool the range would give a relation that is not a function, since more than one patient is assigned to one nurse.
Answer:
The distance between the points is approximately 6.4
Step-by-step explanation:
The given coordinates of the points are;
(2, -2), and (6, 3)
The distance between two points, 'A', and 'B', on the coordinate plane given their coordinates, (x₁, y₁), and (x₂, y₂) can be found using following formula;

Substituting the known 'x', and 'y', values for the coordinates of the points, we have;

Therefore, the distance between the points, (2, -2), and (6, 3) = √(41) ≈ 6.4.