Given:
Right triangle with one angle 45°
To find:
The value of q and r.
Solution:
Opposite to θ = 16
Adjacent to θ = r
Hypotenuse = q
Using trigonometric ratio formula:
![$\tan \theta =\frac{\text{Opposite side to } \theta}{\text{Adjacent to } \theta}](https://tex.z-dn.net/?f=%24%5Ctan%20%5Ctheta%20%3D%5Cfrac%7B%5Ctext%7BOpposite%20side%20to%20%7D%20%5Ctheta%7D%7B%5Ctext%7BAdjacent%20to%20%7D%20%5Ctheta%7D)
![$\tan 45^\circ =\frac{16}{r}](https://tex.z-dn.net/?f=%24%5Ctan%2045%5E%5Ccirc%20%3D%5Cfrac%7B16%7D%7Br%7D)
The value of tan 45° = 1
![$1 =\frac{16}{r}](https://tex.z-dn.net/?f=%241%20%3D%5Cfrac%7B16%7D%7Br%7D)
Do cross multiplication, we get
r = 16
Using trigonometric ratio formula:
![$\sin \theta =\frac{\text{Opposite side to } \theta}{\text{Hypotenuse}}](https://tex.z-dn.net/?f=%24%5Csin%20%5Ctheta%20%3D%5Cfrac%7B%5Ctext%7BOpposite%20side%20to%20%7D%20%5Ctheta%7D%7B%5Ctext%7BHypotenuse%7D%7D)
![$\sin 45^\circ =\frac{16}{q}](https://tex.z-dn.net/?f=%24%5Csin%2045%5E%5Ccirc%20%3D%5Cfrac%7B16%7D%7Bq%7D)
The value of sin 45° =
.
![$\frac{1}{\sqrt{2} } =\frac{16}{q}](https://tex.z-dn.net/?f=%24%5Cfrac%7B1%7D%7B%5Csqrt%7B2%7D%20%7D%20%20%3D%5Cfrac%7B16%7D%7Bq%7D)
Do cross multiplication, we get
![q=16\sqrt{2}](https://tex.z-dn.net/?f=q%3D16%5Csqrt%7B2%7D)
The value of r is 16 and the value of q is
.
<span>$849.33 weekly earned
</span>
Answer:
$12.69
Step-by-step explanation:
3 times 4.23=12.96
Answer:
Ok :)
Step-by-step explanation: