First aquarium dimensions:
Length = 6 m.
Width = 4 m and
Height = 2 meter.
Second aquarium dimensions:
Length = 8 m.
Width = 9 m and
Height = 3 meter.
We know formula for volume of a cuboidal box = Length*Width*Height.
Plugging values of length, width and height of first aquarium in formula of volume. We get
V1 = 6*4*2 = 48 m^3.
Plugging values of length, width and height of second aquarium in formula of volume. We get
V2 = 8*9*3 = 216 m^3.
In order to find the total cubic meters of space do the sea turtles have in their habitat, we need to add both volumes.
Therefore, Total voulme of both aquarium = V1 +V2 = 48+216 = 264 m^3.
Therefore, total 264 m^3 cubic meters of space the sea turtles have in their habitat.
Answer: Vertical
Step-by-step explanation:
Answer:
The missing length is 2x+5
Step-by-step explanation:
Given equation of volume of cuboid is V= 
Figure show that
Length of cuboid is ?
Width of cuboid is (x+4)
Height of cuboid is (x+2)
The volume of cuboid is given by
V=Length x Width x Height
Let Length be (bx+a)
The volume of cuboid will be
![V=(bx+a)[x^{2}+4x+2x+8 ]](https://tex.z-dn.net/?f=V%3D%28bx%2Ba%29%5Bx%5E%7B2%7D%2B4x%2B2x%2B8%20%5D)
![V=bx[x^{2}+6x+8]+a[x^{2}+6x+8]](https://tex.z-dn.net/?f=V%3Dbx%5Bx%5E%7B2%7D%2B6x%2B8%5D%2Ba%5Bx%5E%7B2%7D%2B6x%2B8%5D)
![V=[bx^{3}+6bx^{2}+8bx]+[ax^{2}+6ax+8a]](https://tex.z-dn.net/?f=V%3D%5Bbx%5E%7B3%7D%2B6bx%5E%7B2%7D%2B8bx%5D%2B%5Bax%5E%7B2%7D%2B6ax%2B8a%5D)
![V=[bx^{3}+(6b+a)x^{2}+(8b+6a)x+8a]](https://tex.z-dn.net/?f=V%3D%5Bbx%5E%7B3%7D%2B%286b%2Ba%29x%5E%7B2%7D%2B%288b%2B6a%29x%2B8a%5D)
On comparing coefficient with given equation of volume
We get,
b=2 and 8a=40
Therefore, the value of a is 5 and b is 2
Thus, The missing length is bx+a=2x+5
Answer:
21-7x
Step-by-step explanation: gather like terms
25-4=21 -9x+2x=-7x
I think 12 minutes because if you take 9 divide it by 3/4 you get 12
