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2 years ago

Solve each of the following equations. Show its solution set on a number line. Check your answers. 3 |2-x|=-6

Mathematics

2 answers:

sineoko [7]2 years ago

6 0

The answer is that x=4

DochEvi [55]2 years ago

4 0

X=4

3 x 2= 6
3 x -4= -12
—————-
-6

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Which of the following is/are appropriate measure(s) of

Katarina [22]

Step-by-step explanation:

you can relate both the unit in one form

6 0

2 years ago

when 6 is subtracted from the square of a number, the result is 5 times the number. Find the negative solution.

sveta [45]

When 6 is subtracted from the square of a number, the result is 5 times the number, then the negative solution is -1

<h3><u>Solution:</u></h3>

Given that when 6 is subtracted from the square of a number, the result is 5 times the number

To find: negative solution

Let "a" be the unknown number

Let us analyse the given sentence

square of a number = $a^2$

6 is subtracted from the square of a number = $a^2 - 6$

5 times the number = $5 \times a$

<em><u>So we can frame a equation as:</u></em>

6 is subtracted from the square of a number = 5 times the number

$a^2 - 6 = 5 \times a\\\\a^2 -6 -5a = 0\\\\a^2 -5a -6 = 0$

<em><u>Let us solve the above quadratic equation</u></em>

For a quadratic equation $ax^2 + bx + c = 0$ where $a \neq 0$

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here in this problem,

$a^2-5 a-6=0 \text { we have } a=1 \text { and } b=-5 \text { and } c=-6$

Substituting the values in above quadratic formula, we get

$\begin{array}{l}{a=\frac{-(-5) \pm \sqrt{(-5)^{2}-4(1)(-6)}}{2 \times 1}} \\\\ {a=\frac{5 \pm \sqrt{25+16}}{2}=\frac{5 \pm \sqrt{49}}{2}} \\\\ {a=\frac{5 \pm 7}{2}}\end{array}$

We have two solutions for "a"

$\begin{array}{l}{a=\frac{5+7}{2} \text { and } a=\frac{5-7}{2}} \\\\ {a=\frac{12}{2} \text { and } a=\frac{-2}{2}}\end{array}$

We have asked negative solution. So a = -1

Thus the negative solution is -1

6 0

3 years ago

What is the answer?<br> (2 3/8 - 1/4)x1/8=?

Andrews [41]

2 3/8 - 1/4 = 2 1/8 x 1/8 = 17/64.

To do this, you first need to do the problem in the (). You have to turn 1/4 with a denominator of eight, so the fraction becomes 2/8. 2 3/8 - 2/8 = 2 1/8. Now we have to turn 2 1/8 into an improper fraction by doing whole number x denominator + numerator. 17/8 x 1/8 = 17/64.

7 0

3 years ago

Solve for x b=1/6π n ^2 x

Setler [38]

Answer:

$\large\boxed{x=\dfrac{6b}{\pi n^2}}$