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Olin [163]
3 years ago
8

What is the solution for the following system of equations?Use ANY method to solve.

Mathematics
2 answers:
mezya [45]3 years ago
8 0
Its c.
If you will substitute those numbers to the pair of equations, both will be true.

1=-3+4
1=3-2
Vika [28.1K]3 years ago
7 0

Answer:

The aswer is c

Step-by-step explanation:


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each side of triangle xyz has length 9 .Find the area of the region inside the circumcircle of the triangle but outside the tria
mote1985 [20]

Answer:

The area of the region inside the circumcircle of the triangle but outside the triangle is

A=\frac{27}{4}[\pi-3\sqrt{3}]\ units^2

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

Find the area of triangle

we have an equilateral triangle

Applying the law of sines

A_t=\frac{1}{2}(b^2)sin(60^o)

where b is the length side of the equilateral triangle

we have

b=9\ units

A_t=\frac{1}{2}(81)sin(60^o)

A_t=\frac{1}{2}(81)\frac{\sqrt{3}}{2}

A_t=81\frac{\sqrt{3}}{4}\ units^2

step 2

Find the area of circle

The area of the circle is equal to

A_c=\pi r^{2}

The formula to calculate the radius of the circumcircle of the triangle equilateral is equal to

r=b\frac{\sqrt{3}}{6}

where b is the length side of the equilateral triangle

we have

b=9\ units

substitute

r=(9)\frac{\sqrt{3}}{6}

r=3\frac{\sqrt{3}}{2}\ units

Find the area

A_c=\pi (3\frac{\sqrt{3}}{2})^{2}

A_c=\frac{27}{4} \pi\ units^2

step 3

Find the area of the shaded region

we know that

The area of the region inside the circumcircle of the triangle but outside the triangle is equal to the area pf the circle minus the area of triangle

so

A=(\frac{27}{4} \pi-81\frac{\sqrt{3}}{4})\ units^2

Simplify

A=\frac{27}{4}[\pi-3\sqrt{3}]\ units^2

6 0
3 years ago
The product of eight and a number Q is at least 32
Dennis_Churaev [7]
" the product " means multiply

the product of 8 and a number Q is at least 32...

8Q > = 32 (thats greater then or equal to)
3 0
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Phoenix [80]

Answer:

true

Step-by-step explanation:

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3 years ago
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Please answer quickly and correctly please answer all question
Nata [24]

Answer:

1)d

2)

6)b

7)d,c,b,a

8)a,b

8 0
3 years ago
Solve: –x – 7 = –2x – 11
Ivan
<span>Simplifying (7 + -2x)(11 + -2x)(x) = 0 Reorder the terms for easier multiplication: x(7 + -2x)(11 + -2x) = 0 Multiply (7 + -2x) * (11 + -2x) x(7(11 + -2x) + -2x * (11 + -2x)) = 0 x((11 * 7 + -2x * 7) + -2x * (11 + -2x)) = 0 x((77 + -14x) + -2x * (11 + -2x)) = 0 x(77 + -14x + (11 * -2x + -2x * -2x)) = 0 x(77 + -14x + (-22x + 4x2)) = 0 Combine like terms: -14x + -22x = -36x x(77 + -36x + 4x2) = 0 (77 * x + -36x * x + 4x2 * x) = 0 (77x + -36x2 + 4x3) = 0 Solving 77x + -36x2 + 4x3 = 0 Solving for variable 'x'. Factor out the Greatest Common Factor (GCF), 'x'. x(77 + -36x + 4x2) = 0 Factor a trinomial. x((7 + -2x)(11 + -2x)) = 0 </span>
8 0
3 years ago
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