Answer:
531.6g
Explanation:
Total moles of glucose in this case is: 886/180= 4.922 (mole)
For every 1 mole glucose we get 6 mole water
-> Mole of water is: 4.922 * 6= 29.533 (mole)
weight of water is 18. Therefore, total weight of water that we will have from 886g of glucose are: 25.933*18= 531.6g
That water is a universal solvent and that sugar is soluble?
Answer:
V₂ = 448.44 L
Explanation:
Given data:
Initial volume = 5.00 L
Initial temperature = 24°C
Final volume = ?
Final temperature = -27000°C
Solution:
Final temperature = -27000 + 273 = 26727 K
Initial temperature = 24 +273 = 297 K
The given problem will be solve through the Charles Law.
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
V₂ = V₁T₂/T₁
V₂ = 5.00 L × 26727 K / 297 k
V₂ = 133635 L.K / 298 K
V₂ = 448.44 L
Answer:
option b is correct
as it have same number of atoms on both the reactant and product side.
