Answer:
Mass = 206.38 g
Explanation:
Given data:
Mass of calcium chloride = 80.0 g
Mass of silver chloride formed = ?
Solution:
Chemical equation:
CaCl₂ + 2AgNO₃ → Ca(NO₃)₂ + 2AgCl
Number of moles of CaCl₂:
Number of moles = mass/molar mass
Number of moles = 80.0 g/ 110.98 g/mol
Number of moles = 0.72 mol
Now we will compare the moles of CaCl₂ and AgCl
CaCl₂ : AgCl
1 : 2
0.72 : 2/1×0.72 = 1.44 mol
Mass of silver chloride:
Mass = number of moles × molar mass
Mass = 1.44 mol × 143.32 g/mol
Mass = 206.38 g
Basically the temperature it would take to boil water which is 100 degrees celcius, the equivalent of 212 degrees farenheight
Answer:
c. can have a large cumulative effect
Explanation:
Noncovalent interactions between molecules are weaker than covalent interactions. Noncovalent interactions between molecules are of various types which include van der Waals forces, hydrogen bonding, and electrostatic interactions or ionic bonding.
van der Waals forces are weak interactions found in all molecules. They include dipole-dipole interactions - formed due to the differences in the electronegativity of atoms - and the London dispersion forces.
Hydrogen Bonds results when electrons are shared between hydrogen and a strongly electronegative atoms like fluorine, nitrogen, oxygen. The hydrogen acquires a partial positive charge while the electronegative atom acquires a partial negative. This results in attraction between hydrogen and neighboring electronegative molecules.
Ionic bonds result due to the attraction between groups with opposite electrical charges, for example in common salt between sodium and chloride ions.
Even though these noncovalent interactions are weak, cumulatively, they exert strong effect. For example, the high boiling point of water and the crystal structure of ice are due to hydrogen bonding.
1.2 Cups to 0.2839 Liters (I think if I did my math right)
Answer:
4.8 %
Explanation:
We are asked the concentration in % by mass, given the molarity of the solution and its density.
0.8 molar solution means that we have 0.80 moles of acetic acid in 1 liter of solution. If we convert the moles of acetic acid to grams, and the 1 liter solution to grams, since we are given the density of solution, we will have the values necessary to calculate the % by mass:
MW acetic acid = 60.0 g/mol
mass acetic acid (the solute) = 0.80 mol x 60 g / mol = 48.00 g
mass of solution = 1000 cm³ x 1.010 g/ cm³ (1l= 1000 cm³)
= 1010 g
% (by mass) = 48.00 g/ 1010 g x 100 = 4.8 %