What mass of manganese(II) chloride must react with sulfuric acid to release 52.5 mL of hydrogen chloride gas at STP?

1 answer:

7 0

The balanced chemical reaction is written as:

MnCl2(s)+H2SO4(aq)→MnSO4(aq)+2HCl(g)

We are given the amount of hydrochloric acid to be produced in the reaction. This value will be the starting point for the calculations.We do as follows:

.0525 L HCl ( 1 mol / 22.4 L ) ( 1 mol MnCl2 / 2 mol HCl ) (125.84 g / 1 mol ) = 0.15 g MnCl2

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