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Answer:
2.97 × 10¹³ g
Explanation:
First, we have to calculate the biomass the is burned. We can establish the following relations:
- 2.47 acre = 10,000 m²
- 10 kg of C occupy an area of 1 m²
- 50% of the biomass is burned
The biomass burned in the site of 400,000 acre is:
Let's consider the combustion of carbon.
C(s) + O₂(g) ⇒ CO₂(g)
We can establish the following relations:
- The molar mass of C is 12.01 g/mol
- 1 mole of C produces 1 mole of CO₂
- The molar mass of CO₂ is 44.01 g/mol
The mass of produced is CO₂:
Answer:
number of moles of =4.16mol
Explanation:
experiment data:
temperature= =273+22 k=295k
pressure=1.007 atm
volume is missing so assuming volume-=100L
using ideal law relationship
ideal gas means gas which occupies negligible space and there is no interaction between the molecules of gases.
PV=nRT
put all the experimental data, we get
n=4.15 mol
number of moles of =4.16mol