Question

Direction: Solve the given problems.

Answer 1

○=> Solution (6) :

Ratio of two numbers = 2:3

The larger number = 6

Let the smaller number be x.

Which means :

$=\tt 2 : 3 \: = \: x : 6$

$= \tt \frac{2}{3} = \frac{x}{6}$

$=\tt 2 \times 6 = 3 \times x$

$=\tt 12 = 3x$

$=\tt x = \frac{12}{3}$

$\hookrightarrow\color{plum}\tt \: x = 4$

▪︎Therefore, the smaller number = 4

○=> Solution (7) :

36 compared to 6 = $\tt \frac{36}{6}$

Let the number be x.

Which means :

$= \tt \frac{36}{6} = \frac{x}{3}$

$=\tt \frac{36 \div 2}{6 \div 2} = \frac{x}{3}$

$=\tt \frac{36}{6} = \frac{18}{3}$

▪︎Therefore, the fractional number $\tt \frac{18}{3}$ is equal to $\tt \frac{36}{6}$.

○=> Solution (8) :

Number of Rose's for 24 red Rose's = 6

This can be written in a ratio as 24:6

Number of roses = 8

Let the number of red roses for these roses be x.

Which means :

$=\tt \frac{24}{6} = \frac{x}{8}$

$=\tt 24 \times 8 = 6 \times x$

$=\tt 192 = 6x$

$=\tt x = \frac{192}{6}$

$\hookrightarrow \color{plum}\tt x = 32$

▪︎Therefore, 32 red roses are there if there are 8 roses.

○=> Solution (9) :

Number of children for 2 adults = 7

This can be written in a ratio as 7:2

Number of children in the plaza = 21

Let the number of adults be x.

Which means :

$= \tt \frac{7}{2} = \frac{21}{x}$

$=\tt7 \times x = 2 \times 21$

$=\tt 7x = 42$

$=\tt x = \frac{42}{7}$

$\hookrightarrow \color{plum}\tt \: x = 6$

▪︎Therefore, 6 adults were there in the plaza.

○=> Solution (10) :

Cost of 12 pencils = P60

Cost of 1 pencil :

$= \tt \frac{60}{12}$

$=\tt P5$

Thus, the cost of one pencil = P5

Cost of 25 pencils :

= Cost of one pencil × 25

$=\tt 5 \times 25$

$\color{plum}=\tt \: P \: 125$

▪︎Therefore, the cost of 25 pencils = P125