2, since 2x 1/3 is 2/3, which is less than 3/4.
Answer:
x1= -4, x2 = 7
Step-by-step explanation:
Move expression to the left-hand side:
1/4x-3/4-7/x=0
Write all the numerators above a common denominator:
x^2 - 3x - 28 /4x =0
When the quotient of expressions equal 0, the numerator has to be 0
x^2 + 4x - 7x - 28 = 0
x(x+4) - 7(x+4) =0
(x+4) × (x-7) =0
Separate into possible cases:
x+4=0
x-7=0
Answer:
- -35/3, -140/3, - 560/3, -2240/3
- 7, -28, 112, - 448
Step-by-step explanation:
<u>The terms are:</u>
<u>Given:</u>
- a₁ = a₂ + 35
- a₃ = a₄ + 560
<u>Use the nth term formula:</u>
- a₂ = a₁r
- a₃ = a₁r²
- a₄ = a₁r³
<u>Substitute:</u>
- a₁ = a₁r + 35 ⇒ a₁(1 - r) = 35
- a₁r² = a₁r³ + 560 ⇒ a₁(1 - r)r² = 560
<u>Divide the second equation by the first:</u>
- r² = 560/35
- r² = 16
- r = √16
- r = ± 4
<u>Use the first equation to find the first term:</u>
- a₁( 1 ± 4) = 35
- 1. a₁ = 35/-3 = -35/3
- 2. a₁ = 35/5 = 7
<u>We have two sequences:</u>
r = 4
- -35/3, -140/3, - 560/3, -2240/3
r = -4
I think it’s frictional force sorry if it’s wron g
