Ask question

Ask question

All categories

2 years ago

8

f(x)=-2x-1 g(x)=-1/2x+1/2 Which statements, if any, are true about these functions? I. The function f(g(x)) = x for all real x.

II. The function g(f(x)) = x for all real x. III. Functions f and g are inverse functions.

2 answers:

barxatty [35]2 years ago

8 0

Answer:

None of statements are true

Step-by-step explanation:

Vesnalui [34]2 years ago

7 0

Answer:

III. Functions f and g are inverse functions.

Step-by-step explanation:

You might be interested in

The annual interest rate on a 15-year

rewona [7]

Answer:

The amount of interest paid is $22,500

Step-by-step explanation:

Firstly, we need the number of $1 in $450,000

That would simply be $450,000/$1 = 450,000

5 cents is same as 5/100 = $0.05

so we have to multiply 450,000 by 0.05

we have this as;

450,000 * $0.05 = $22,500

6 0

2 years ago

The scale reads 18kg a dog weighed at an animal clinic. About how many pounds dose the dog weigh

zhenek [66]

Answer:

Step-by-step explanation:

80 pds

5 0

2 years ago

Read 2 more answers

If JK = KL, find JL.

mafiozo [28]

Answer:

umm your funny if u think im going to answer that im sorry but my brain is not working rn i prolly should go take a nap

Step-by-step explanation:

3 0

2 years ago

What is the true solution to 2 In e in5x = 2 In 15?

just olya [345]

Answer:

x = 3

Step-by-step explanation:

Using the rules of logarithms

ln x = ln y ⇒ x = y

ln e = 1

Given

2 ln e ln 5x = 2 ln 15 ( divide both sides by 2 )

ln e ln 5x = ln 15

ln 5x = ln 15, hence

5x = 15 ( divide both sides by 5 )

x = 3

5 0

2 years ago

Read 2 more answers

Enter the number in standard notation.

Jobisdone [24]

<h3>The length in standard notation is 0.05 meter</h3>

<em><u>Solution:</u></em>

Given that,

Jeremy measured the length of an ant as $5 \times 10^{-2}\ meter$

We have to write the length in standard notation

From given,

$Length = 5 \times 10^{-2}\\\\Length = \frac{5}{10^{2}}\\\\Simplify\\\\Length = \frac{5}{100}\\\\Length = 0.05$

Thus the length in standard notation is 0.05 meter

<em><u>Method 2:</u></em>

$length = 5 \times 10^{-2}\ meter$

Use the exponent of 10 to determine how many places to move the decimal point

Since exponent is -2, is negative

Thus, we have to move the decimal point to right 2 places

$5 \times 10^{-2} = 0.05$

Thus the length in standard notation is 0.05 meter

5 0

2 years ago