Question Solve: x - 18 = –103. Provide your answer belo
2 answers:
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Hello here is a solution ;
Easy
the easiest way is to imagine that you have a rectangle with a corner cut off
the area of the figure=area of rectangle-area cut off
area that was cut off was a triangle
area of rectangle=length times width
area of triangle=1/2base times height
so we draw imaginary lines like in attachment
find area of rectangle
legnth=9 inch
width=9 inch
area=9 times 9=81 in^2
triangle
the top part is ?+5=9, so the base of triangle=4
the side is ?+4=9, so the base is 5
area=1/2 times 4 times 5=10 in^2
area=rectangle-triangle
area=81-10=71 in^2
the easiest way is to imagine that you have a rectangle with a corner cut off
the area of the figure=area of rectangle-area cut off
area that was cut off was a triangle
area of rectangle=length times width
area of triangle=1/2base times height
so we draw imaginary lines like in attachment
find area of rectangle
legnth=9 inch
width=9 inch
area=9 times 9=81 in^2
triangle
the top part is ?+5=9, so the base of triangle=4
the side is ?+4=9, so the base is 5
area=1/2 times 4 times 5=10 in^2
area=rectangle-triangle
area=81-10=71 in^2
X-y=6 Equation 1
x+y=4 Equation 2
To graph the given system of equation, first find x and y-intercept of each equation.
x-y=6
When y=0
x=6 Point is (6,0)
When x=0
-y=6
y=-6 Point is (0,-6)
Now x-intercept and y-intercept for equation 2.
x+y=4
When x=0
y=4 Point is (0,4)
When y=0
x=4 Point is (4,0)
Now plot these points on the graph, the lines intersect each other at point (5,-1), which is the solution of the given system.
Answer: (5,-1)
x+y=4 Equation 2
To graph the given system of equation, first find x and y-intercept of each equation.
x-y=6
When y=0
x=6 Point is (6,0)
When x=0
-y=6
y=-6 Point is (0,-6)
Now x-intercept and y-intercept for equation 2.
x+y=4
When x=0
y=4 Point is (0,4)
When y=0
x=4 Point is (4,0)
Now plot these points on the graph, the lines intersect each other at point (5,-1), which is the solution of the given system.
Answer: (5,-1)