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4 years ago

What is the domain of this function?

Mathematics

2 answers:

Alex4 years ago

7 0

Answer:

Correct option is:

D. {-1,3,5}

Step-by-step explanation:

We have to find the domain of the function defined in figure.

The domain of f(x)=y is all the possible values of x for which the function is defined

Here, f(-1)=2

f(3)=6

and f(5)=8

Hence, all the possible values of x are:

{-1,3,5}

Hence, Correct option is:

D. {-1,3,5}

bulgar [2K]4 years ago

4 0

Domain is the independent variables or the x.
so i say D {-1,3,5} based on the arrows

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Saturn's average distance from then sun is about 900 million miles.what is that distance in scientific notation?

IRINA_888 [86]

900,000,000. move the decimal until you have a number between 1-10 so move it 8 times and you'll have 9×10^8

3 0

3 years ago

Simply the following 2m⁵×5m³×7m²

Ganezh [65]

Answer:

$2m^5\cdot 5m^3\cdot 7m^2=70\cdot m^{10}$

Step-by-step explanation:

Simplify the expression

$2m^5\cdot 5m^3\cdot 7m^2$

Calculate the product of the coefficients:

2*5*7=70

Compute the product of the variables. Since they are all the same letter, sum their exponents:

$m^5\cdot m^3\cdot m^2=m^{5+3+2}=m^{10}$

Combine the results:

$\boxed{2m^5\cdot 5m^3\cdot 7m^2=70\cdot m^{10}}$

3 0

3 years ago

Find 3x2 − y3 − y3 − z if x = 3, y = −2, and z = −5.

IceJOKER [234]

3x²-y³ - y³ - z if x = 3, y = -2, z = -5

Simply plug in all the values :)

3(3²) - (-2³) - (-2³) - (-5)

Simplify.

3(9) + 2³ + 2³ + 5

Simplify.

27 + 8 + 8 + 5

Simplify.

35 + 13

Simplify.

48

~Hope I helped!~

4 0

4 years ago

Every employee works 7 hours per day. every employee works 5 days per week. every employee works 49 weeks per year. how many day

andriy [413]

To determine the number of days that an employee work in a week, we simply use dimensional analysis and multiplying the number of works per week with the number of weeks in total for a year. That is,
employee works = (5 days per week)(49 weeks per year)
=245 days

4 0

4 years ago

Read 2 more answers

Neptune is an average distance of 4.5 × 10^9 km from the Sun. Estimate the length of the Neptunian year using the fact that the

zlopas [31]

Answer:

164.32 earth year

Step-by-step explanation:

distance of Neptune, Rn = 4.5 x 10^9 km

distance of earth, Re = 1.5 x 10^8 km

time period of earth, Te = 1 year

let the time period of Neptune is Tn.

According to the Kepler's third law

T² ∝ R³

$\left ( \frac{T_{n}}{T_{e}} \right )^{2}=\left ( \frac{R_{n}}{R_{e}} \right )^{3}$

$\left ( \frac{T_{n}}{1} \right )^{2}=\left ( \frac{4.5\times10^{9}}}{1.5\times10^{8}}} \right )^{3}$

Tn = 164.32 earth years

Thus, the neptune year is equal to 164.32 earth year.

Step-by-step explanation:

3 0

4 years ago