Answer:
Based on the info given, no calculation needed .... it's 1.00 Liter
Explanation:
All you've given is the molar concentration which by definition is the moles solute per Liter of solution. That is, 3.5M H₂SO₄(aq) solution means 3.5 mole H₂SO₄ per 1.0 Liter.
Answer:
This is the conversion factor, we have to use:
44 g / 1mol
Explanation:
The reaction for the methane combustion is:
CH₄ + 2O₂ → CO₂ + 2H₂O
First of all we use this conversion factor to determine the moles of methane, we used.
50.6 g . 1 mol / 16 g = 3.16 mol
So ratio is 1:1, then 3.16 mol of methane will produce 3.16 moles of CO₂
To calculate the grams of produced dioxide:
3.16 mol . 44 g / 1mol = 139.04 g
The equation for work is
W = PdV
and it is integrated and limits are the conditions of state 1 and state 2
If the gas is ideal and the expansion is isothermal, then P = nRT/V and the equation can be integrated with respect to V
If the process is adiabatic, the equation P1V1^g = PV^g can be used to substitue P in terms of conditions of State 1.
