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scZoUnD [109]
2 years ago
8

Explain constraint of domain on parabola graphs

Mathematics
1 answer:
scZoUnD [109]2 years ago
6 0

Answer:The set of possible values for the independent variable is called the domain. Similarly, there are constraints on the values for any dependent variable. ... Graphs of functions are traditionally drawn with the independent variable on the horizontal axis and the dependent variable on the vertical axis.

Step-by-step explanation:

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If x + 3y = 7 and x - 3y =7 , then find y<br><br> Please help me
telo118 [61]

Answer:

x + 3y = 7 , x - 3y = 7 : y = , x = 7

Step-by-step explanation:

\left[\begin{array}{ccc}x + 3y = 7\\x - 3y = 7\end{array}\right]

Isolate x for x + 3y = 7 : x = 7 - 3y:

Substitute x = 7 - 3y:

\begin{bmatrix}7-3y-3y=7\end{bmatrix}

Isolate y for 7 - 3y - 3y = 7 : y = 0:

For x =7-3y

Substitute y = 0

x=7-3 * 0

7 - 3 * 0 = 7

x = 7

The solution to the system of equations are:

y=0,\:x=7

Hope I helped. If so, may I get brainliest and a thanks?

Thank you. Have a good day! =)

3 0
3 years ago
(a + 8)(b + 3)<br><br> ab + 8a + 3b + 24<br> ab + 3a + 8b + 24<br> 11ab<br> 24ab
pochemuha
The answer is ab+3a+8b+24.
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2 years ago
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The sum of matrices A and B is C.
GuDViN [60]

Answer:

Step-by-step explanation: -3

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3 years ago
Describe a situation where it would be better to use a fraction than a decimal or a percentage
AysviL [449]
I prefer to use fractions for some irrational numbers.

For example, 1/3 is equal to an infinite 0.3333333333333333...
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Find the equation of a line that runs through
MAVERICK [17]

Answer:

The equation of a line that runs through  (-6,2) and is parallel to a line with a slope of (-1/4)     is  x + 4y  - 2 = 0

Step-by-step explanation:

Slope of the parallel  equation is m 1 = (-1/4)

<em>If the two liner are parallel the, slope of both lines are equal.</em>

⇒The slope of the equation of line = m2  = m1  = -(1/4)

The point (x0, y0)  = (-6,2)

Now, by THE POINT SLOPE FORMULA:  The equation of a line is given as

( y - y0)  =  m (x -x0)

Now, here the equation of line is given as:

y - 2 = (\frac{-1}{4}) (x - (-6))   \implies  4(y-2) = -1(x + 6)

or, 4y - 8 + x + 6 = 0

or, x + 4y  - 2 = 0

Hence, the required line equation is  x + 4y  - 2 = 0

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3 years ago
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