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2 years ago

8

Explain constraint of domain on parabola graphs

1 answer:

scZoUnD [109]2 years ago

6 0

Answer:The set of possible values for the independent variable is called the domain. Similarly, there are constraints on the values for any dependent variable. ... Graphs of functions are traditionally drawn with the independent variable on the horizontal axis and the dependent variable on the vertical axis.

Step-by-step explanation:

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Let f(x)= x^2-4x-c. Find a nonzero value of c such that f(c)=c.

Dimas [21]

Answer:

The nonzero value of c will be:

$c = 6$

Step-by-step explanation:

Given the function

$f\left(x\right)=\:x^2-4x-c$

$f\left(c\right)=\:c^2-4c-c$

as

$f(c) = c$

so

$c=\:c^2-4c-c$

switching the sides

$c^2-4c-c=c$

subtract c from both sides

$c^2-4c-c-c=c-c$

$c^2-6c=0$

$c\left(c-6\right)=0$

Using the zero factor principle

$\:If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

$c=0\quad \mathrm{or}\quad \:c-6=0$

so, the solutions to the quadratic equations are:

$c=0,\:c=6$

Therefore, a nonzero value of c will be:

$c = 6$

5 0

2 years ago

Which equation represents the relationship shown in the graph below?

fomenos

I believe the answer is B
:)

3 0

3 years ago

Katya treated everyone in theater to a pizza party. She bought 12 pizzas and six 2-liters of soda. The bill was $137.64 (before

sweet-ann [11.9K]

let the price of pizza and soda( per 2 litre bottle) be x and y

from 1st condition

12x+2y=137.6.....(1)

from 2nd condition

x+y =11.95.......(2)

multiply eq. (2) by 2

2x+2y=23.9.....(3)

subtracting (1) and (3)

12x+2y=137.6

2x+2y= 23.9

10x = 113.7

x=113.7/10

x=11.37

2(11.37)+2y=23.9

22.74+2y=23.9

2y=23.9-22.7

2y=1.2

y=0.6

So the prices of the pizza and soda are 11.37 and 0.6 dollars.

4 0

2 years ago

There are 946 milliters in a quart there are 2 pints in a quart

devlian [24]

Answer:

Answer: There are 473 milliliters in 1 pint. ... 946 ml in 1 quart

Step-by-step explanation:

3 0

2 years ago

Plzzzzzzzzzzz help me

oksano4ka [1.4K]

The second table does not represent a function

6 0

2 years ago