Answer:
AC:PC=8:5
Step-by-step explanation:
Draw a vertical line from D perpendicular to AB. Denote D' the intersection with I, and D'' intersection with AB. Consider the right triangle ADD". Realize that the lengths |DD"| and |DD'| are 3:5, which follows from triangles ADD" and MDD' being similar. This means that I bisects the trapezoid's height in a ratio 3:5.
Next, draw a vertical line perpendicular to AB, going through P. Denote P" the intersection of this line with AB, and denote P' the intersection of this line with DC. Observe that because lines CD || AB, the angles <BAC and <ACD are congruent. This implies triangles APP" and CPP' are similar with a side ratio 3:5, i.e., |AP|/|PC|=3/5. Therefore |AC|/|PC|=(|AP|+|PC|)/|PC|=|AP|/|PC|+1 = 8/5
The ratio AC:PC is 8:5
Answer:
see explanation
Step-by-step explanation:
The zeros of the graph are x = - 4 and x = 2 , then the factors are
(x + 4)(x - 2) and
y = a(x + 4)(x - 2) ← a is a multiplier
To find a use any other point on the graph and substitute into the equation
Using (0, - 8 ) , then
- 8 = a(4)(- 2) = - 8a ( divide both sides by - 8 )
1 = a
y = (x + 4)(x - 2) = x² + 2x - 8
with b = 2 and c = - 8
The graph is increasing from the turning point ( vertex) to the right
vertex = (- 1, - 9 )
Increasing in the interval [- 1, ∞ )
Yes you do make to a proper fraction
Answer:
D
Step-by-step explanation:
I think it is $10 for 20%