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sukhopar [10]
2 years ago
12

Which expression is equivalent to 4 square root 6 divided by 3 root 2

Mathematics
2 answers:
denis-greek [22]2 years ago
7 0

Answer:

The expression is equivalent to 4 square root 6 divided by 3 root 2 is:

8/3

Step-by-step explanation:

Given expression:

4 square root 6 divided by 3 root 2

\frac{4\sqrt{6}}{3\sqrt{2} }

=\frac{4\sqrt{2*2*2}}{3\sqrt{2} }

=\frac{4\sqrt{2*2^{2} }}{3\sqrt{2} }

square root of 2² = 2 hence,

=\frac{4*2\sqrt{2}}{3\sqrt{2} }

=\frac{8\sqrt{2}}{3\sqrt{2} }

Common terms in the numerator and denominator cancels each other out

=\frac{8}{3}

By solving the expression using simple mathematical rules, we got an equivalent expression of

\frac{4\sqrt{6}}{3\sqrt{2} } = \frac{8}{3}

mezya [45]2 years ago
7 0

Answer:

\frac{4\sqrt{3} }{3}

Step-by-step explanation:

Find a common factor between the numerator and the denominator, so that they may cancel out one another.

\frac{4\sqrt{6} }{3\sqrt{2} } \\\\=\frac{4\sqrt{3*2} }{3\sqrt{2} } \\\\=\frac{4\sqrt{3}\sqrt{2}  }{3\sqrt{2} }

Then by cancelling out the square root of 2:

\frac{4\sqrt{3} }{3}

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Given ACM, angle C=90º. AP=9, PM=12. Find AC, CM, AM.
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Answer:

AM = 25, AC = 15, CM = 20

Step-by-step explanation:

The given parameters are;

In ΔACM, ∠C = 90°, \overline{CP} ⊥ \overline{AM}, AP = 9, and PM = 16

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\overline{AM} = \overline{AP} + PM = 9 + 16 = 25

\overline{AM} = 25

\overline{AC}² = \overline{AP}² + \overline{CP}² = 9² +  \overline{CP}²

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Similarly we get;

\overline{CM}² = 16² + \overline{CP}²

Therefore, we get;

\overline{AC}² + \overline{CM}² = 9² +  \overline{CP}² + 16² + \overline{CP}² = \overline{AM}² = 25²

2·\overline{CP}² = 25² - (9² + 16²) = 288

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\overline{AC} = √(9² +  12²) = 15

\overline{AC} = 15

From, \overline{CM}² = 16² + \overline{CP}², we get;

\overline{CM} = √(16² + 12²) = 20

\overline{CM} = 20.

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Step-by-step explanation:

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