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vesna_86 [32]
2 years ago
7

Factorise the following.​

Mathematics
1 answer:
zepelin [54]2 years ago
8 0

Answer:

Step-by-step explanation:

i). \frac{48a^3}{6a}=\frac{6\times 8\times a\times a^2}{6a}

          =\frac{6a}{6a}\times 8a^2

          = 8a²

ii). \frac{72a^3b^4c^5}{8ab^2c^3} = \frac{8\times 9\times a\times a^2\times b^2\times b^2\times c^2\times c^3}{8ab^2c^3}

                = \frac{8ab^2c^3}{8ab^2c^3}\times 9a^2b^2c^2

                = 9a²b²c²

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Answer:

4 types of questions one will be to read, 2nd will be to subtract, one will be to add, the next will be to find missing numbers each are expressed below.

Step-by-step explanation:

This is a two-circle Venn diagram. The 1st circle is A, and the 2nd circle is B. The complete Venn diagram represents the union of A and B, or A ∪ B.

Just intersect is A ∩ B

Just intersect B ∩ A

A∩B=   A∩B={2}  differs significantly from below.

A  small ∁

 (sometimes denoted as ~A or ¬A)

is pronounced as: "A complement" (or "not A", for the other notations)

means: the new set gets everything that is in the universe but is outside of A; it's okay if the element is in B, just so long as it is not also in A

in terms of the elements: {1, 2, 3, 4} – {1, 2}

my answer:  = A ∁ ={3,4}

A – B (or A \ B)in terms of the elements: {1, 2} – {2, 3}

A – B = {1}

A∪B)=¬(A∪B)in terms of the elements: = {1, 2, 3, 4} – {2}

in terms of the elements: {1, 2, 3, 4} – ({1, 2} ∪ {2, 3}) = {1, 2, 3, 4} – {1, 2, 3}

(4) elements here are just the remainder my answer: my answer:(A∪B)={4}

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Here is the problem.....√(15x + 10) = 2x+3

to remove the square root, we do the opposite which is to square everything.

(√(15x + 10))² = (2x + 3)²      (the square negates the square root)
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15x + 10 = 4x² + 12x + 9      (subtract 15x and 10 from each side)
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x - 1 = 0                4x + 1 = 0
x = 1                      4x = -1
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place both into the equation to check for reasonableness...we see the negative number is not reasonable, but the x value of 1 is a solution.

answer is 1
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