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vesna_86 [32]
3 years ago
7

Factorise the following.​

Mathematics
1 answer:
zepelin [54]3 years ago
8 0

Answer:

Step-by-step explanation:

i). \frac{48a^3}{6a}=\frac{6\times 8\times a\times a^2}{6a}

          =\frac{6a}{6a}\times 8a^2

          = 8a²

ii). \frac{72a^3b^4c^5}{8ab^2c^3} = \frac{8\times 9\times a\times a^2\times b^2\times b^2\times c^2\times c^3}{8ab^2c^3}

                = \frac{8ab^2c^3}{8ab^2c^3}\times 9a^2b^2c^2

                = 9a²b²c²

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3 years ago
Factor (z-5)(z+4)=52​
Ipatiy [6.2K]

Good Afternoon! Here is your answer step by step!

Let's solve your equation step-by-step.

(z−5)(z+4)=52

Step 1: Simplify both sides of the equation.

z2−z−20=52

Step 2: Subtract 52 from both sides.

z2−z−20−52=52−52

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Step 3: Factor left side of equation.

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Step 4: Set factors equal to 0.

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Answer:

z=−8 or z=9

Have a blessed day! ❤

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