Step-by-step explanation:
Assuming the data is as shown, restaurant X has a mean service time of 180.56, with a standard deviation of 62.6.
The standard error is SE = s/√n = 62.6/√50 = 8.85.
At 95% confidence, the critical value is z = 1.960.
Therefore, the confidence interval is:
180.56 ± 1.960 × 8.85
180.56 ± 17.35
(163, 198)
Restaurant Y has a mean service time of 152.96, with a standard deviation of 49.2.
The standard error is SE = s/√n = 49.2/√50 = 6.96.
At 95% confidence, the critical value is z = 1.960.
Therefore, the confidence interval is:
152.96 ± 1.960 × 6.96
152.96 ± 13.64
(139, 167)
X=4 , I believe this is the right answer
Answer:
- A public in-state college charges less for in-state tuition than for out-of-state tuition.
- Tara will most likely have to pay room and board expenses at an out-of-state public college, but might be able to commute to a public college in state.
Explanation:
If Tara wants to study out of state she could face higher tuition costs; public universities generally favor their residents with lower tuition costs, contrary to the charge for students who comes from other states.
Also, if she wants to study outside the state, Tara would have to analyze the costs of a residence and food that she will have to cover if she studies outside the state. On the contrary, if she studies in the state she could live with her family and only cover the transportation costs.
hope this helps!
Answer:
72178.4777
Step-by-step explanation:
