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Taya2010 [7]
3 years ago
6

HELP PICTURE IS SJOWN

Mathematics
1 answer:
jek_recluse [69]3 years ago
3 0
Letter B is the answer

Number of sides (n) = 8
Apothem (a) = 18.11 units
Side (s) = 15 units

Area of Octagon = (1/2)n*a*s
A of O= (1/2)*8*18.11*15
A of O= 1086.6 units^2


Area of Square = s^2
A of S = 15^2
A of S = 225 units^2


Area of Shaded Region = A of O - A of S
A of S.R. = 1086.6 units^2 - 225 units^2
A of S.R. = 861.6 units^2
A of S.R. = 862 units^2



LETTER B
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If two standard six-sided dice are tossed, what is the probability that a 5 is rolled on at least one of the two dice? express y
zaharov [31]
We define the probability of a particular event occurring as:
\frac{number\ of \ desired\ outcomes}{number\ of\ possible\ outcomes}

What are the total number of possible outcomes for the rolling of two dice? The rolls - though performed at the same time - are <em>independent</em>, which means one roll has no effect on the other. There are six possible outcomes for the first die, and for <em>each </em>of those, there are six possible outcomes for the second, for a total of 6 x 6 = 36 possible rolls.

Now that we've found the number of possible outcomes, we need to find the number of <em>desired</em> outcomes. What are our desired outcomes in this problem? They are asking for all outcomes where there is <em>at least one 5 rolled</em>. It turns out, there are only 3:

(1) D1 - 5, D2 - Anything else, (2), D1 - Anything else, D2 - 5, and (3) D1 - 5, D2 - 5

So, we have \frac{3}{36} = \frac{1}{12} probability of rolling at least one 5.
6 0
3 years ago
Using (x + a) (x + b) = x² + (a + b) x + ab, evaluate 75 x 77
Gre4nikov [31]

(x + a) (x + b) = x² + (a + b) x + ab

75 * 77=

=(70+5)(70+7)

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4 0
3 years ago
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frutty [35]

260 units2 is the answer

3 0
3 years ago
Read 2 more answers
From 1960 to 2010, a certain money stock measure was growing at the rate of approximately 43e(1/2)x billion dollars per decade,
natulia [17]

Answer:

1222 billion dollars.

Step-by-step explanation:

To find the total increase from 1960 to 2010, we need to find the growth of each decade and sum them all:

In the period 1960-1970, we have x = 1, and the growth is:

y(1) = 43e(1/2) = 70.895

In the period 1970-1980, we have x = 2, and the growth is:

y(2) = 43e(2/2) = 116.8861

The growth in the following 3 periods are:

y(3) = 43e(3/2) =192.7126

y(4) = 43e(4/2) = 317.7294

y(5) = 43e(5/2) =523.8472

So the total growth in the period 1960 - 2010 is:

Total = y(1) + y(2) + y(3) + y(4) + y(5)

Total = 70.895 + 116.8861+192.726+317.7294+523.8472

Total = 1222.08\ billion\ dollars

Rounding to the nearest billion dollars, we have a total of 1222 billion dollars.

6 0
3 years ago
A restaurant owner made a list of the number of meals ordered last night. She found that 42 people ordered chicken Parmesan, 39
jasenka [17]

Answer:

29/110

Step-by-step explanation:

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5 0
4 years ago
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