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3 years ago

HELP PICTURE IS SJOWN

Mathematics

1 answer:

jek_recluse [69]3 years ago

3 0

Letter B is the answer

Number of sides (n) = 8
Apothem (a) = 18.11 units
Side (s) = 15 units

Area of Octagon = (1/2)n*a*s
A of O= (1/2)*8*18.11*15
A of O= 1086.6 units^2

Area of Square = s^2
A of S = 15^2
A of S = 225 units^2

Area of Shaded Region = A of O - A of S
A of S.R. = 1086.6 units^2 - 225 units^2
A of S.R. = 861.6 units^2
A of S.R. = 862 units^2

LETTER B

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What is the probability that a randomly selected dunlop tire lasts between 65000 and 80000 miles?

taurus [48]

You are looking at around 81.5% i assume by shifting the standard deviation by the same amount on both sides the % will not change
i split the normal distribution curve into 8 pieces
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3 years ago

I need help with my geometry homework assp

Mekhanik [1.2K]

Its just pythagorean theorem so you would do this:

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3 years ago

<img src="https://tex.z-dn.net/?f=15x%5E%7B2%7D" id="TexFormula1" title="15x^{2}" alt="15x^{2}" align="absmiddle" class="latex-f

Genrish500 [490]

Answer:

not sure of what you were asking so it's simplified below.

Step-by-step explanation:

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Note: best i could do with what was given.

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3 years ago

Discs of a radius 4cm are cut from a rectangular plastic sheet of length 84cm and width 24 cm

Aleonysh [2.5K]

Answer: 40

Step-by-step explanation:

Given

Radius of disc $r=4\ cm$

The dimension of the sheet is $84\times 24\ cm^2$

Area of a single disc

$\Rightarrow a=\pi r^2=\frac{22}{7}\times 4^2\\\\\Rightarrow a=\frac{352}{7}\ cm^2$

Area of sheet

$\Rightarrow A=84\times 24=2016\ cm^2$

No. of discs that can be cut off the sheet are

$\Rightarrow n=\dfrac{A}{a}=\dfrac{2016}{\frac{352}{7}}=\dfrac{2016\times7}{352}\\\Rightarrow n\approx 40$

The total area of the disc is

$\Rightarrow na=40\times\frac{352}{7}=2011.428\ cm^2$

Sheet wasted

$\Rightarrow A-na=2016-2011.428=4.57\ cm^2$

7 0

3 years ago

Amiraneli [1.4K]

$\huge\mathfrak{\underline{Answer:}}$

❒ The length of longest side of first Trianlge :

‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ $\large\bf{32\:cm}$

__________________________________________

$\large\bf{\underline{given:}}$

Two similar triangles
Perimeter of first Trianlge is 74 cm
Side length of second triangle are 4.5cm , 6cm and 8cm

$\setlength{\unitlength}{1 cm}\begin{picture}(0,0)\thicklines\qbezier(1, 0)(1,0)(3,3)\qbezier(5,0)(5,0)(3,3)\qbezier(5,0)(1,0)(1,0)\put(2.85,3.2){$\bf A$}\put(0.5,-0.3){$\bf C$}\put(5.2,-0.3){$\bf B$}\end{picture}$

$\setlength{\unitlength}{0.75 cm}\begin{picture}(0,1)\thicklines\qbezier(1, 0)(1,0)(3,3)\qbezier(5,0)(5,0)(3,3)\qbezier(5,0)(1,0)(1,0)\put(2.85,3.2){$\bf P$}\put(0.5,-0.3){$\bf R$}\put(5.2,-0.3){$\bf Q$}\end{picture}$

__________________________________________

$\large\bf{\underline{To \:find :}}$

The length of longest side of first Trianlge

__________________________________________

$\large\bf{\underline{Perimeter\:of\: second\: triangle:}}$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\large\bf{=sum\:of\:all\:sides}$

‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\large\bf{=4.5+6+8}$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\large\bf{=18.5}$

❒ The ratio between the perimeter of two triangles :

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\large\bf{=\frac{perimeter\:of\:1st\: triangle}{perimeter\:of\:2nd\: triangle}}$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\large\bf{=\frac{74}{18.5}}$

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎ $\large\bf{=4:1}$

❒ The two triangles are similar , therefore the ratio of their sides will also be similar , i.e 4:1