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alex41 [277]
3 years ago
11

Find all real values of $t$ that satisfy the equation $t^2 = 324$. the answer is 18.

Mathematics
2 answers:
Annette [7]3 years ago
5 0

Ur account got ha ked again...

well...

ill let you see for

zhuklara [117]3 years ago
4 0

Answer:

the real values that satisfy the equation are:

t=18,\:t=-18

Step-by-step explanation:

Given the equation

$t² = 324$

Let us solve the equation

t^2=324

\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}

t=\sqrt{324},\:t=-\sqrt{324}

as

\sqrt{324}=18-\sqrt{324}=-18

so

t=18,\:t=-18

Thus, the real values that satisfy the equation are:

t=18,\:t=-18

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