Answer:
A. 131.9 s
B. 0.13 m/s
Explanation:
From the question given above, the following data were obtained:
Mass (m) = 490 Kg
Height (h) = 17 m
Power (P) = 0.83 hp
Time (t) =?
Velocity (v) =.?
Next, we shall convert 0.83 hp to Watts. This can be obtained as follow:
1 hp = 745.7 Watts
Therefore,
0.83 hp = 0.83 hp × 745.7 Watts / 1 hp
0.83 hp = 618.931 Watts
Thus, 0.83 hp is equivalent to 618.931 Watts.
A. Determination of the time.
Mass (m) = 490 Kg
Height (h) = 17 m
Power (P) = 618.931 Watts
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) =?
Power = Energy / time
P = mgh / t
618.931 = 490 × 9.8 × 17 / t
618.931 = 81634 / t
Cross multiply
618.931 × t = 81634
Divide both side by 618.931
t = 81634 / 618.931
t = 131.9 s
Therefore, it will take 131.9 s to lift the beam.
B. Determination of the constant velocity.
We'll begin by calculating the force. This can be obtained as follow:
Mass (m) = 490 Kg
Acceleration due to gravity (g) = 9.8 m/s²
Force (F) =?
Force = mass × acceleration
Force = 490 × 9.8
Force = 4802 N
Finally, we shall determine the constant velocity as follow:
Force (F) = 4802 N
Power (P) = 618.931 Watts
Velocity (v) =?
P = F × v
618.931 = 4802 × v
Divide both side by 4802
v = 618.931 / 4802
v = 0.13 m/s
Thus, the constant speed at which the beam moves upward is 0.13 m/s
