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3 years ago

If you travel 4 miles around a circle with a radius of 1 mile, what is the central angle (q)?

Mathematics

1 answer:

mixer [17]3 years ago

4 0

Answer:

229.18 degrees

Step-by-step explanation:

The circumference of a circle with radius r is 2×pi×r.

So if it has a radius of 1 mile, then the circumference is 2×pi×1=2pi miles.

So if we travel 4 miles, then the percentage of this circle we traveled is 4/(2pi)=63.66% approximately.

There are 360 degrees in a circle and we want to how much of that rotation belongs to traveling 4 miles of the circumference of a circle that measures 2pi miles. So 63.66%×360 degrees =229.18 degrees.

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Please help, thanks!

Westkost [7]

Answer:

$x=99^{\circ},\\y=81^{\circ}$

Step-by-step explanation:

The sum of the interior angles of a polygon with $n$ sides is $180(n-2)$ . Since the shape in the figure has 5 sides, the sum of its interior angles is $180(5-2)=180\cdot 2=540^{\circ}$ .

Therefore, we can set up the following equation:

$95+125+105+116+x=540,\\441+x=540,\\x=\boxed{99^{\circ}}$

Since $\angle x$ and $\angle y$ make up one side of a line, they are supplementary, as each side of a line is $180^{\circ}$ .

Thus, we have:

$x+y=180,\\99+y=180,\\y=\boxed{81^{\circ}}$

4 0

3 years ago

How to solve 3x^2-33x+54

TiliK225 [7]

A=3
B=-33
C=54
Plot it into the Quadratic equation which is -b +- Square root of: b^2 -4ac.Divided by 2a.
You can find you answer when you plot it into this! If you do not get what the Quadratic equation is check online.

I hope this helps!

3 0

4 years ago

Find the set of solutions for the linear system.

Illusion [34]

Answer:

The system has infinitely many solutions.

$\left\begin{array}{ccc}x_1&=&-\frac{1}{3}x_2-\frac{16}{9}x_4-\frac{2}{9} \\x_2&=&s_1\\x_3&=&-\frac{4}{3}x_4+\frac{1}{3} \\x_4&=&s_2\end{array}\right$

Step-by-step explanation:

To find the solution for this system of linear equations $-3x_1-x_2+4x_3=2\\-3x_3 - 4x_4 = -1$ you must:

Step 1: Transform the augmented matrix to the reduced row echelon form.

A matrix is a rectangular arrangement of numbers into rows and columns.

A system of equations can be represented by an augmented matrix.

In an augmented matrix, each row represents one equation in the system and each column represents a variable or the constant terms.

This is matrix that represents the system

$\left[ \begin{array}{ccccc} -3 & -1 & 4 & 0 & 2 \\\\ 0 & 0 & -3 & 4 & -1 \end{array} \right]$

The augmented matrix can be transformed by a sequence of elementary row operations to the matrix.

There are three kinds of elementary matrix operations.

Interchange two rows (or columns).
Multiply each element in a row (or column) by a non-zero number.
Multiply a row (or column) by a non-zero number and add the result to another row (or column).

Using elementary matrix operations, we get that

Row Operation 1: Multiply the 1st row by -1/3

Row Operation 2: Multiply the 2nd row by -1/3

Row Operation 3: Add 4/3 times the 2nd row to the 1st row

$\left[ \begin{array}{ccccc} 1 & \frac{1}{3} & 0 & \frac{16}{9} & - \frac{2}{9} \\\\ 0 & 0 & 1 & \frac{4}{3} & \frac{1}{3} \end{array} \right]$

Step 2: Interpret the reduced row echelon form

The reduced row echelon form of the augmented matrix is

$\left[ \begin{array}{ccccc} 1 & \frac{1}{3} & 0 & \frac{16}{9} & - \frac{2}{9} \\\\ 0 & 0 & 1 & \frac{4}{3} & \frac{1}{3} \end{array} \right]$

which corresponds to the system

$x_1+\frac{1}{3}x_2+ \frac{16}{9}x_4=-\frac{2}{9} \\x_3+ \frac{4}{3}x_4=\frac{1}{3}$

We see that the variables $x_2, x_4$ can take arbitrary numbers; they are called free variables. Let $x_2=s_1$ , $x_4=s_2$ . All solutions of the system are given by

$\left\begin{array}{ccc}x_1&=&-\frac{1}{3}x_2-\frac{16}{9}x_4-\frac{2}{9} \\x_2&=&s_1\\x_3&=&-\frac{4}{3}x_4+\frac{1}{3} \\x_4&=&s_2\end{array}\right$

The system has infinitely many solutions.

8 0

4 years ago

Write a quadratic function whose zeros are 11 and -3

Marat540 [252]

F(x)= a(x-11)(x+3)
I believe that’s so

5 0

3 years ago

Which equation is y = –3x2 – 12x – 2 rewritten in vertex form?

AlekseyPX

Answer:

The vertex form is y = -3(x + 2)² + 10

Step-by-step explanation:

* Lets revise how to put the quadratic in the vertex form

- The general form of the quadratic is y = ax² + bx + c, where

a , b , c are constants

# a is the coefficient of x²

# b is the coefficient of x

# c is the numerical term or the y-intercept

- The vertex form of the quadratic is a(x - h)² + k, where a, h , k

are constants

# a is the coefficient of x²

# h is the x-coordinate of the vertex point of the quadratic

# k is the y-coordinate of the vertex point of the quadratic

- We can find h from a and b ⇒ h = -b/a

- We find k by substitute the value of h instead of x in the general form

of the quadratic

k = ah² + bh + c

* Now lets solve the problem

∵ y = -3x² - 12x - 2

∵ y = ax² + bx + c

∴ a = -3 , b = -12

∵ h = -b/2a

∴ h = -(-12)/2(-3) = 12/-6 = -2

- Lets find k

∴ k = -3(-2)² - 12(-2) - 2 = -3(4) + 24 - 2 = -12 + 24 - 2 = 10

* Lets writ the vertex form

∵ y = a(x - h)² + k

∵ a = -3 , h = -2 , k = 10

∴ y = -3(x - -2)² + 10

∴ y = -3(x + 2)² + 10

* The vertex form is y = -3(x + 2)² + 10

6 0

3 years ago

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