Answer:
Cost of material is $245.31
Step-by-step explanation:
Let dimension of box,
<em>The length of this base is twice the width.</em>
<em>∴ </em>x = 2y
Volume of box = 10 m³
∴ xyz = 10
⇒ 2y²z = 10
⇒ y²z = 5
<em>Material for the base costs $15 per square meter.</em>
Total cost of base = 15xy
Total cost of base = 30y² [∵ x = 2y ]
<em>Material for the sides costs $9 per square meter.</em>
Total cost of side = 9(2xz+2zy)
Total cost of side = 18(xz+yz)
Total cost of material for container = 30y² + 18(xz+yz)
[From (i)]
Differentiate w.r.t y
For critical point , C'(y)=0
The minimum cost of container material at
Hence, the cheapest cost of material for container is $245.31
Answer:
146,300,000
Step-by-step explanation:
146,273,011
<u>The hundred thousand place is 100,000</u>
<u />
<u>Step 1: Round</u>
146,273,011
<em>146,300,000</em>
<em />
Answer: 146,300,000
Infinitely Many Solutions because is you simplify either one, you get the same equation as the other.
1 frequency is 1
2 is 3
3 is 4
4 is 3
last is 3
that's all I understand
hope it helped