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Nonamiya [84]
4 years ago
6

Charlotte finds two landscape gardeners online: the first charges a fixed fee of $20 per job plus $15 per hour for labor, while

the second charges a fixed fee of $90 but only $5 per hour for labor. After how many hours will the second gardener be cheaper than the first?
Mathematics
2 answers:
lions [1.4K]4 years ago
8 0

There are two ways to find the answer to this question.

Way #1:  

Draw both lines on a graph and see where line-1 goes higher than line-2.

In order to do this, you first have to write the equations for both lines, or at least identify the slope and intercept for each one.

Way #2:

If you have to do that anyway, you might as well just find the solutioin of the two equations, and not bother drawing the graph.

First gardener:  Cost1 = 20 + 15H

Second gardener:  Cost2 = 90 + 5H

The second gardener starts out more expensive . . . before they even start working, the first one wants $20 but the second one wants $90.

After that, though, once they start working, their prices come together . . . for every hour they work, the first one wants another $15 but the second one only wants another $5 .

Eventually, after enough hours, their total prices will be equal, and AFTER that, the second one will actually cost less than the first one.

Since we have already written the equations for both of their prices, we can easily (if we have enough scratch paper left over) find the number of hours where their prices are equal.

First gardener:  Cost1 = 20 + 15H

Second gardener:  Cost2 = 90 + 5H

Costs are equal when  20 + 15H = 90 + 5H

Subtract 20 from each side:  15H = 70 + 5H

Subtract 5H from each side:  10H = 70

Divide each side by 10 : H = 7

For less than 7 hours of work, #1 costs less.  For exactly 7 hours of work, they both charge the same amount ($125). For MORE than 7 hours of work, #2 costs less.

Damm [24]4 years ago
6 0

$15 per hour for labor plus $5 per hour for labor

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<u>Step-by-step explanation:</u>

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2. MNM Corporation gives each of its employees an aptitude test. The scores on the test are normally distributed with a mean of
antiseptic1488 [7]

Answer:

a) Let X the random variable that represent the scores of a population, and for this case we know the distribution for X is given by:

X \sim N(75,15)  

Where \mu=75 and \sigma=25

The distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

b) \mu represent the true average for the scores of the aptitude test

c) We can calculate the z scores and we got:

z = \frac{70.14-75}{\frac{15}{\sqrt{25}}}= -1.62

z = \frac{82.14-75}{\frac{15}{\sqrt{25}}}= 2.38

And we can calculate the probability with this difference:

P(-1.62

d) We can calculate the z scores and we got:

z = \frac{82.68-75}{\frac{15}{\sqrt{25}}}= 2.56

And we can calculate the probability with this difference:

P(Z

e) We can calculate the z scores and we got:

z = \frac{78.69-75}{\frac{15}{\sqrt{25}}}= 1.23

And we can calculate the probability with this difference:

P(Z

Step-by-step explanation:

a. What are the expected value, the standard deviation, and the shape of the sampling distribution of \bar X?

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Let X the random variable that represent the scores of a population, and for this case we know the distribution for X is given by:

X \sim N(75,15)  

Where \mu=75 and \sigma=25

The distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

b. What is the random variable in this problem? Define it in words.

\mu represent the true average for the scores of the aptitude test

c. What is the probability that the average aptitude test score in the sample will be between 70.14 and 82.14?

We can calculate the z scores and we got:

z = \frac{70.14-75}{\frac{15}{\sqrt{25}}}= -1.62

z = \frac{82.14-75}{\frac{15}{\sqrt{25}}}= 2.38

And we can calculate the probability with this difference:

P(-1.62

d. What is the probability that the average aptitude test score in the sample will be greater than 82.68?

We can calculate the z scores and we got:

z = \frac{82.68-75}{\frac{15}{\sqrt{25}}}= 2.56

And we can calculate the probability with this difference:

P(Z

e. What is the probability that the average aptitude test score in the sample will be less than 78.69?

We can calculate the z scores and we got:

z = \frac{78.69-75}{\frac{15}{\sqrt{25}}}= 1.23

And we can calculate the probability with this difference:

P(Z

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tankabanditka [31]
So 3/4 of an hour is 45 minutes (3/4 × 60min)
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Then for 5 walls, he will take 5 × 15 = 75 minutes

Answer: He will take 1 hour 15 minutes to paint 5 walls
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