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damaskus [11]
2 years ago
6

Please I need the answer right now will mark you brainliest ​

Physics
2 answers:
iVinArrow [24]2 years ago
6 0

Answer:

that's for frequency other answers are coming soon

Dmitrij [34]2 years ago
3 0

Answer:

Explanation:

what do u need help with

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Nonrenewable energy resources do not include which of the following?
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Hydrogen fuel cells is the answer
8 0
2 years ago
Read 2 more answers
In February 1955, a paratrooper fell 370 m from an airplane without being able to open his chute but happened to land in snow, s
nevsk [136]

a) 0.94 m

The work done by the snow to decelerate the paratrooper is equal to the change in kinetic energy of the man:

W=\Delta K\\-F d = \frac{1}{2}mv^2 - \frac{1}{2}mu^2

where:

F=1.1 \cdot 10^5 N is the force applied by the snow

d is the displacement of the man in the snow, so it is the depth of the snow that stopped him

m = 68 kg is the man's mass

v = 0 is the final speed of the man

u = 55 m/s is the initial speed of the man (when it touches the ground)

and where the negative sign in the work is due to the fact that the force exerted by the snow on the man (upward) is opposite to the displacement of the man (downward)

Solving the equation for d, we find:

d=\frac{1}{2F}mu^2 = \frac{(68 kg)(55 m/s)^2}{2(1.1\cdot 10^5 N)}=0.94 m

b) -3740 kg m/s

The magnitude of the impulse exerted by the snow on the man is equal to the variation of momentum of the man:

I=\Delta p = m \Delta v

where

m = 68 kg is the mass of the man

\Delta v = 0-55 m/s = -55 m/s is the change in velocity of the man

Substituting,

I=(68 kg)(-55 m/s)=-3740 kg m/s

7 0
3 years ago
A block with a mass of 9.00 kg is pulled at a constant speed across a horizontal tabletop with a spring scale. The scale reads 6
snow_tiger [21]

Answer:0.69

Explanation:

Coefficient of kinetic friction=f/R=61.8/90=0.69

7 0
3 years ago
Which parts of the graph would increase if all of earth's polar ice melts? Which part would decrease?
Sedbober [7]

Answer:

the answer to the question is the part that is reflected by clouds and atmosphere 26%

8 0
3 years ago
Problem I Marcella (see warmup problem, above) gets her car moving steadily at 4m/s but suddenly someone stops ahead to assist h
Nady [450]

Answer:

Explanation:

a) KE = (1/2) * m * (v^{2}) = F * d = 14m * 200N = 2800 m/N or 2.8 * 10^{3} m/N

b) 0J and 0m/s (if Marcella stopped after going 14 meters)

c)  Known from part (a) that KE = 2800 J = F1 * d1,

    2800J = F1 * (14m - 1m)  => F1 = 2800J/13m = 215.384 N

   

3 0
3 years ago
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