velocity of the physics instructor with respect to bus

acceleration of the bus is given as

acceleration of instructor with respect to bus is given as

now the maximum distance that instructor will move with respect to bus is given as




so the position of the instructor with respect to door is exceed by

so it will be moved maximum by 3 m distance
Answer:
B
Explanation:
<em>A. His speed is 0 m/s
</em>
<em>B. His velocity is 12 m/s
</em>
<em>C. His velocity is 0 m/s
</em>
<em>D. His acceleration is 12 m/s</em>
Total distance traveled by John = 120 + 120 = 240 meters
Total time taken by John to cover the distance = 10 + 10 = 20 s
<em>Average speed of John = total distance traveled/total time taken</em>
= 240/20 = 12 m/s
Hence, the average speed/velocity of John throughout the journey is 12 m/s.
The correct option is B.
Answer:
Explanation:
Speed and medium are properties of a wave which is in common within an area of the spectrum of visible light. i.e;
Their medium of propagation
They both travel at the same speed ( speed of light )
The properties mentioned above are properties that define that wave is found within an area spectrum for visible light.
Wish I Could Help You!
Answer:
The height of the building is approximately 156.58 m
Explanation:
The mass of the ball dropped from rest from the building top = 0.660 kg
The time in which the ball falls, t = 5.65 seconds
The height, h, of the building is given from the following equation of motion;
h = u·t + ¹/₂·g·t²
Where;
u = The initial velocity of the ball = 0 m/s
g = The acceleration due to gravity = 9.81 m/s²
Plugging in the values, we have;
h = 0 × 5.65 + ¹/₂ × 9.81 × 5.65² ≈ 156.58 m
The height of the building, h ≈ 156.58 m.
Hey there,
Your question states: <span>How long does it take for light from a star that is 8 light-years away to reach earth?
It take just about
(</span>
8 earth years) <span> for light from a star that is 8 light-years away to reach earth. That is how </span>

it would take.
Hope this helps.
~Jurgen