Answer:
The lowest frequency is 45.01 Hz.
The second lowest frequency is 135.03 hz.
The highest frequency is 19993.4 Hz.
Explanation:
Given that,
Length = 1.85 m
Range of frequency = 20 hz - 20000 Hz
Temperature = 18.0°C
Suppose, the tube is closed at one end lowest frequency
, second lowest frequency
and highest frequency
We need to calculate the velocity of sound
Using formula of sound velocity
Put the value into the formula
(a). For closed end,
We need to calculate the lowest and second lowest frequency
Using formula of frequency
[tyex]f_{n}=(2n+1)\times\dfrac{v}{4l}[/tex]
If n =0
Put the value into the formula
If n = 1
Put the value into the formula
Now, The maximum audible range is 20000 Hz.
We need to calculate the value of n
Using formula of frequency
Put the value into the formula
We need to calculate the maximum frequency
Using formula of frequency
Put the value into the formula
Hence, The lowest frequency is 45.01 Hz.
The second lowest frequency is 135.03 hz.
The highest frequency is 19993.4 Hz.