A visual example of this is one my mother showed me. She drew a circle and laid out a piece of yarn around it so that it imitated the perfect shape of the circle. She laid out another piece that was as long as the circle's radius. She wrapped the longer piece around the shorter one, and I saw that it could wrap around it three times and still have at least 0.14 units left. I'm not sure if this helps, but the circumference of this circle is 18.84 cm ^2. I hope I answered your question.
Answer: 
Step-by-step explanation:
1. You know that:
- The roped-off area whose width is represented with <em>x,</em> it is created around a rectangular museum.
- The dimensions of the rectangular museum are: 30 ft by 10 ft.
- The combined area of the display and the roped-off area is 800 ft².
2. The area of the rectangular museum can be calculated with:
Where 
is the lenght and 
is the width.
You have that the lenght and the width in feet are:
3. Let's call 
the width of the roped-off area. Then, the combined area is:
Where
4. Substitute values and simplify. Then:
Hello from MrBillDoesMath!
Answer:
1/ 91.4
Discussion:
Evaluate 1/ ( 3x^3 + 5.2y) when x = 3, y = 2.
1/ (3 (3)^3 + 5.2(2)) =
1/ ( 3 * 27 + 10.4) =
1/ ( 81 + 10.4) =
1/ (91.4) =
.0109 (approx)
Thank you,
MrB
volume cylinder
=3.14×2^2×5
=62.8 cubic inches
volume sphere
=4/3×3.14×2^3
=33.49
difference between cylinder and sphere
=62.8-33.49
=29.31 cubic sphere
<span>The number 8.5 is being added. </span>
