Find the lowest price you would have to pay in each of the following situations.

If a small boy, in 30 days, saved $1.00 to spend in your store, how much did he save each day?

ivolga24 [154]

Answer:

3 cents for 29 days and 4 cents for 1 day

Step-by-step explanation:

1.00 dollar / 30 days = .03 cents

3 cents x 30 = .99 cents

3 cents for 29 days and 4 cents for 1 day

6 0

3 years ago

Read 2 more answers

A computer can be classified as either cutting dash edge or ancient. Suppose that 94% of computers are classified as ancient.

taurus [48]

Answer:

(a) 0.8836

(b) 0.6096

(c) 0.3904

Step-by-step explanation:

We are given that a computer can be classified as either cutting dash edge or ancient. Suppose that 94% of computers are classified as ancient.

(a) Two computers are chosen at random.

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 2 computers

r = number of success = both 2

p = probability of success which in our question is % of computers

that are classified as ancient, i.e; 0.94

LET X = Number of computers that are classified as ancient

So, it means X ~ $Binom(n=2, p=0.94)$

Now, Probability that both computers are ancient is given by = P(X = 2)

P(X = 2) = $\binom{2}{2}\times 0.94^{2} \times (1-0.94)^{2-2}$

= $1 \times 0.94^{2} \times 1$

= 0.8836

(b) Eight computers are chosen at random.

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 8 computers

r = number of success = all 8

p = probability of success which in our question is % of computers

that are classified as ancient, i.e; 0.94

LET X = Number of computers that are classified as ancient

So, it means X ~ $Binom(n=8, p=0.94)$

Now, Probability that all eight computers are ancient is given by = P(X = 8)

P(X = 8) = $\binom{8}{8}\times 0.94^{8} \times (1-0.94)^{8-8}$

= $1 \times 0.94^{8} \times 1$

= 0.6096

(c) Here, also 8 computers are chosen at random.

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 8 computers

r = number of success = at least one

p = probability of success which is now the % of computers

that are classified as cutting dash edge, i.e; p = (1 - 0.94) = 0.06

LET X = Number of computers classified as cutting dash edge

So, it means X ~ $Binom(n=8, p=0.06)$

Now, Probability that at least one of eight randomly selected computers is cutting dash edge is given by = P(X $\geq$ 1)

P(X $\geq$ 1) = 1 - P(X = 0)

= $1 - \binom{8}{0}\times 0.06^{0} \times (1-0.06)^{8-0}$

= $1 - [1 \times 1 \times 0.94^{8}]$

= 1 - $0.94^{8}$ = 0.3904

Here, the probability that at least one of eight randomly selected computers is cutting dash edge is 0.3904 or 39.04%.

For any event to be unusual it's probability is very less such that of less than 5%. Since here the probability is 39.04% which is way higher than 5%.

So, it is not unusual that at least one of eight randomly selected computers is cutting dash edge.

7 0

2 years ago

Train a leaves new york at 9am eastern time on monday, headed for los angeles at a constant rate of 40 miles per hour. on the sa

nlexa [21]

We can assume that B leaves Los Angeles not at noon but at 2pm Eastern Time, so 5 hours later than A leaves New York.

In 5 hours A covers 5*40=200 miles. So, A and B together should cover 3,000-200=2,800 miles.

Combined rate = 40 + 60 = 100 miles per hour.

To cover 2,800 miles they'll need 2,800/100=28 hours.

2pm Eastern Time on Monday + 28 hours = 6pm Eastern Time on Tuesday.

Answer: 6:00pm on Tuesday

7 0

3 years ago

Help!!!!!!!!!!!!!!!!!!!!!!!

Nataly [62]

Hello.

Firstly, let's isolate x on the equation:

$\mathsf{f(x) = 3x + 3} \\ \\ \mathsf{y = 3x + 3} \\ \\ \mathsf{-3x = -y + 3} \\ \\ \mathsf{x = \dfrac{-y + 3}{3}}$

Now, we can replace 'x' for 'y' and vice-versa:

$\mathsf{f^{-1}(x) = \frac{-x + 3}{3}`}$

Hope I helped.

4 0

3 years ago

Chester and Mary have pencils in a ratio of 2:4. Together they have 24 pencils. What percentage of the total pencils does Mary h

weeeeeb [17]

She has 67% of the pencils.

Chester:Mary = 2:4 = 1:2
So, in the simplest case:
If Chester has one pencil Mary would have two.
There are three pencils.
Mary has two.
2/3 = 0.667 = 67% (rounded)

3 0

3 years ago

Read 2 more answers