Calculate the acceleration of a 7,000 kg, single-engine airplane just before takeoff when the thrust of its

Physics

1 answer:

Arada [10]3 years ago

3 0

The engine is 10,000 N I think. Hopefully this helps!!

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Which interaction between x-ray photons and matter results in total absorption of the incident photon?

Leno4ka [110]

Answer:

Photoelectric effect

Explanation:

In the photoelectric effect, when an x-ray strikes on a metal surface, the energy is completely absorbed by the metal. If the energy would be equal to or more than work function of metal, electron ejects out. The kinetic energy of the electron which is ejected depends on the energy of the incident radiation and work function of the metal.

4 0

4 years ago

The highest barrier that a projectile can clear is 24.7 m, when the projectile is launched at an angle of 23.0 Â° above the hori

ra1l [238]

Initial velicity Vo.

Sin(23) = 24.7 / Vo
Vo = 24.7/Sin(23)
V0 = 63.2 m/sec

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3 years ago

You hold a small metal ball of mass a height above the floor. You let go, and the ball falls to the floor. Choose the origin of

baherus [9]

Answer:

yᵢ = h

vᵢᵧ = 0

Explanation:

Let initial velocity = u

final velocity = v

height = h

acceleration due to gravity = g

Therefore fro equation of motion,

$v^{2}=u^{2}+2gh$

Here initial velocity is zero.

Hence, $v^{2}=2gh$

$v = \sqrt{2gh}$

but since it points downward and you positive is taken in the up direction

$v = -\sqrt{2gh}$

5 0

4 years ago

A block is pulled across a flat surface at a constant speed using a force of 50 newtons at an angle of 60 degrees above the hori

vladimir2022 [97]

The magnitude of the friction force is 25 N

Explanation:

To solve this problem, we just have to analyze the forces acting on the block along the horizontal direction. We have:

The horizontal component of the pulling force, $F cos \theta$ , where F = 50 N is the magnitude and $\theta=60^{\circ}$ is the angle between the direction of the force and the horizontal; this force acts in the forward direction
The force of friction, $F_f$ , acting in the backward direction

According to Newton's second law, the net force acting on the block in the horizontal direction must be equal to the product between the mass of the block and its acceleration:

$\sum F_x = ma_x$