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3 years ago

7

One ballispicked at random from a box containing 3redballs and 1green balls. If X is the number of redballs picked, find the pro

bability distribution of X.

1 answer:

Paladinen [302]3 years ago

6 0

Answer:

P(X = 0) = 0.25

P(X = 1) = 0.75

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The probability distribution of X.

3 red balls out of 4, one picked, so we can have either 0 red balls or 1 red ball. The probability disitribution is the probability of each outcome.

$P(X = 0) = \frac{1}{4} = 0.25$

$P(X = 1) = \frac{3}{4} = 0.75$

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6. Find the possible values of n in the inequality –3n < 81. A. n > –27 B. n < 27 C. n = –27 D. n = 27

evablogger [386]

-3n < 81...divide both sides by -3, change the inequality sign
n > -81/3
n > - 27 <==

** in an inequality, when dividing/multiplying by a negative number, the inequality sign changes

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3 years ago

A farmer is tracking the amount of corn his land is yielding each year. He finds that the function f(x) = −x2 + 20x + 50 models

polet [3.4K]

Answer:

The crop yield increased by 9 pounds per acre from year 1 to year 10.

Step-by-step explanation:

To solve this we are using the average rate of change formula: $Av=\frac{f(x_2)-f(x_1)}{x_2-x_1}$ , where:

$x_2$ is the second point in the function

$x_1$ is the first point in the function

$f(x_2)$ is the function evaluated at the second point

$f(x_1)$ is the function evaluated at the first point

We know that the first point is 1 year and the second point is 10 years, so $x_1=1$ and $x_2=10$ . Replacing values:

$Av=\frac{-(10)^2+20(10)+50-[-(1)^2+20(1)+50]}{10-1}$

$Av=\frac{-100+200+50-[-1+20+50]}{9}$

$Av=\frac{150-[69]}{9}$

$Av=\frac{150-69}{9}$

$Av=\frac{81}{9}$

$Av=9$

Since $f(x)$ represents the number of pounds per acre and $x$ the number of years, we can conclude that the crop yield increased by 9 pounds per acre from year 1 to year 10.

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3 years ago

It took Howard more than 40 minutes to finish a race. Let t represent Howard’s finishing time.

Nata [24]

I believe the answer will be t + 40 = race time

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3 years ago

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grigory [225]

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3 years ago

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A study was done to determine the stress levels that students have while taking exams. The stress level was found to be normally

Advocard [28]

Answer: 0.1841

Step-by-step explanation:

Given: Mean : $\mu=8.2$

Standard deviation : $\sigma = 1.34$

The formula to calculate z-score is given by :_

$z=\dfrac{x-\mu}{\sigma}$

For x= 9, we have

$z=\dfrac{9-8.2}{1.34}\approx0.60$

For x= 10, we have

$z=\dfrac{10-8.2}{1.34}\approx1.34$

The P-value = $P(0.6$

$=0.9098773-0.7257469=0.1841304\approx0.1841$

Hence, the probability that at your next exam, you will have a stress level between 9 and 10 = 0.1841

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3 years ago