3 years ago

Please help!!!!!!!!!$!$$!

Mathematics

1 answer:

kherson [118]3 years ago

5 0

The answer is two because the value of 18 divided by 9 equals two

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The point A,B,C and D represent the complex number Z1,Z2,Z3 and Z4 and O is the origin. If OABC is a parallelogram, and Z1=1+3i

aleksley [76]

Complex numbers are divided into two parts; real and imaginary parts. The value of Z3 is $5+ 8i$

Given that:

$Z_1 = 1 + 3i$

$Z_2 = 4 + 5i$

Since O is the origin, then:

$C = OA + OB$

This means that:

$Z_3 = Z_1 + Z_2$

So, we have:

$Z_3 = 1 + 3i + 4 + 5i$

Collect like terms

$Z_3 = 1 + 4+ 3i + 5i$

$Z_3 = 5+ 8i$

Hence, complex number Z3 is $5+ 8i$

Read more about complex numbers at:

brainly.com/question/18509723

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2 years ago

2. Given square CANE with diagonals

svlad2 [7]

What’s something goes up but never comes down?

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2 years ago

What is 9.4 x 100 I need a quick answerr

abruzzese [7]

Answer: 940

Explanation: A quick way to think of this is moving the decimal in 9.4 to the right by two decimal places (since there are two zeroes in 100) Hope this helps! :)

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2 years ago

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Find the inverse: f(x)=x+5/3x-1<br><br> f^-1x=

babunello [35]

We have $f(x)=\dfrac{x+5}{3x-1}$ .

To find inverse function $f^{-1}(x)$ we substitute x with $f^{-1}(x)$ and vice-versa to get

$x=\dfrac{f^{-1}(x)+5}{3f^{-1}(x)-1}$

Now solve for $f^{-1}(x)$ . Note that I will use $j$ instead.

$x=\dfrac{j+5}{3j-1} \\x(3j-1)=j+5 \\3jx-x=j+5 \\3jx-x-j-5=0 \\3jx-j=x+5 \\j(3x-1)=x+5 \\j=\dfrac{x+5}{3x-1}$

So we find that $f(x)=f^{-1}$ .

Hope this helps.

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3 years ago

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How do you solve this problem?

pav-90 [236]

the bells will ring at 3:00pm

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3 years ago

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