Answer:
Infinite.
Step-by-step explanation:
Expand:
Add 6 to both sides:
Subtract 3x from both sides:
No matter what x is, it doesn't affect the answer. Thus, the equation is true for all values of x.
The idea is to pair up the terms, factor each sub-group, and then pull out the overall GCF to fully factor.
x^3+5x^2-6x-30
(x^3+5x^2)+(-6x-30)
x^2(x+5)+(-6x-30)
x^2(x+5)-6(x+5)
(x^2-6)(x+5)
-------------
Answer: (x^2-6)(x+5)
<span>Lets say the 1st die rolled a 2 -
there would be 2 combinations for which the sum of dice being < 5 :
2,1
2,2
Now say the 2nd die rolled a 2 -
there would be 2 combinations for which the sum of dice being < 5 :
1,2
2,2
Now we want to count all cases where either dice showed a 2 and sum of the dice was < 5. However note above that the roll (2,2) is counted twice.
So there are three unique dice roll combinations which answer the criteria of at least one die showing 2, and sum of dice < 5:
1,2
2,1
2,2
The total number of unique outcomes for two dice is 6*6=36 .
So, the probability you are looking for is 3/36 = 1/12</span>
<span>factors of 30 that add to 17 are 2 and 15
HOPE THIS HELPS!
</span>
Each point (x, y) is also (domain, range), so the x-values are the domain and the y-values are the range. This answer is A
