All categories

3 years ago

Write the equation of the line that is parallel to y=-3x + 5 and goes through (-4,5)

Mathematics

1 answer:

laila [671]3 years ago

5 0

Step-by-step explanation:

let eqn be y = mx + b

since parallel, the lines have same slope

so, m = -3x

sub (-4 , 5):

5 = -3(-4) + b

b = -7

therefore, eqn is y = -3x - 7

Topic: coordinate geometry

If you like to venture further, feel free to check out my insta (learntionary). It would be best if you could give it a follow. I'll be constantly posting math tips and notes! Thanks!

You might be interested in

PLEASE HURRY ITS TIMED!!!

irina1246 [14]

Answer:

The correct answer is A)

PRISM.

Explanation:

Any 2-dimensional shape formed with straight lines is a polygon. Examples of polygons are:

Quadrilaterals
Hexagons
Pentagons, and
Triangles are all examples of polygons. The name of polygons are usually indicative of the number of sides they have.

Cheers!

5 0

3 years ago

Michael purchased a new office computer system on January 23, 2018, at a cost of $3,791. He does not want to claim bonus depreci

fomenos

Answer:

$3,791

Step-by-step explanation:

$3,791+$3,791-$3,791=3,791 magic!

8 0

3 years ago

Read 2 more answers

One end of a line segment has the coordinates (-6,2). If

CaHeK987 [17]

Answer:

The coordinates of the other end is $(16,2)$

Step-by-step explanation:

Given

$End 1: (-6,2)$

$Midpoint: (5,2)$

Required

Find the coordinates of the other end

Let Midpoint be represented by (x,y);

(x,y) = (5,2) is calculated as thus

$(x,y) = (\frac{x_1 + x_2}{2},\frac{y_1 + y_2}{2})$

$x = \frac{x_1 + x_2}{2}$ and $y = \frac{y_1 + y_2}{2}$

Where $(x_1,y_1) = (-6,2)$ and $(x,y) = (5,2)$

So, we're solving for $(x_2,y_2)$

Solving for $x_2$

$x = \frac{x_1 + x_2}{2}$

Substitute 5 for x and -6 for x₁

$5 = \frac{-6 + x_2}{2}$

Multiply both sides by 2

$2 * 5 = \frac{-6 + x_2}{2} * 2$

$10 = -6 + x_2$

Add 6 to both sides

$6 + 10 = -6 +6 + x_2$

$x_2 = 16$

Solving for $y_2$

$y = \frac{y_1 + y_2}{2}$

Substitute 2 for y and 2 for y₁

$2 = \frac{2 + y_2}{2}$

Multiply both sides by 2

$2 * 2 = \frac{2 + y_2}{2} * 2$

$4 = 2 + y_2$

Subtract 2 from both sides

$4 - 2 = 2 - 2 + y_2$

$y_2 = 2$

$(x_2,y_2) = (16,2)$

Hence, the coordinates of the other end is $(16,2)$

3 0

2 years ago

A regional airport, community college, and city hall building are located at the vertices

love history [14]

Answer:

Aye My Guy You Got The Answer Yet Lol

Step-by-step explanation:

8 0

3 years ago

The length of a regulation soccer field is 110 meters. The diagonal length of the same soccer field is about 133.14 meters. Abou

dexar [7]

Answer:

Step-by-step explanation:

Imagine this as a right angle triangle, where the diagonal length is the hypotenuse, the length is one side, and the width is the other.

We can therefore use Pythagoras' Theorem (or Pythagorean Theorem) to solve. The formula for this is a²+b²=c², where c is the hypotenuse, and a and b are the sides.

We can input the values we know to this formula to get the width. This gives 110²+b²=133.14² or 12100+b²=17 726.2596.

From there subtracting 12100 from both sides gives b²=5626.2596.

Square rooting b isolates it, leaving b=75.0083969.

Since the value of the diagonal was approximate, this can be assumed the b is 75m.

**This content involves Pythagoras' Theorem/Pythagorean Theorem, which you may wish to revise. I'm always happy to help!

8 0

3 years ago