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laila [671]
3 years ago
15

PLZ help me. URGENT. Find all the solutions

Mathematics
1 answer:
pishuonlain [190]3 years ago
6 0

Answer:

5 sec^{2} n-5=0\\\\5sec^{2} =5\\\\sec^{2} =1\\\\\frac{1}{cos^{2}n } =1\\\\answer:=0 ,\pi

Step-by-step explanation:

oh it helps

have a nice day

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kayla has a tshirt store. She sold three times as many white tshirts as blue tshirts. she sold a total of 48 tshirts. How many w
inn [45]
She sold 36 White shirts. Its 48 shirts in total so it would be a ratio of 1/4. 1=Blue shirts and 4=total shirts sold. divide 48 by <span>¼.soyou get 12 shirts. the blue shirts of course.48-12 =36. Another way to check your work is 12 x 3 = 36.

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6 0
3 years ago
-4x-7-3x+4=25 How do I solve by x
Darya [45]

Answer:

x=-4

Step-by-step explanation:

-4x-7-3x+4=25

-7x-3=25

-7x=28

x=-4

4 0
3 years ago
I have 5 questions
LenKa [72]

Answer:number one is b I just answered it don't listen to the person who just randomly answered

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Step-by-step explanation:

5 0
3 years ago
Find b and c so that (5,b,c) is orthogonal to both (1,2,3) and (1,-2,1)
Ipatiy [6.2K]
{5+2b+3c=0
5−2b+c=0
adding both equations u get10+4c=0⇒c=−10/4=−5/2
then5−2b+(−5/2)=0⇒b=(5/2−5)/(−2)=5/2−5/4=5/4
6 0
3 years ago
Read 2 more answers
2x-5=3x^2 find the root of X
Zina [86]

For this case we must solve the following quadratic equation:

3x ^ 2-2x + 5 = 0

Where:

a = 3\\b = -2\\c = 5

The roots are given by:

x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}

Substituting the values we have:

x = \frac {- (- 2) \pm \sqrt {(- 2) ^ 2-4 (3) (5)}} {2 (3)}\\x = \frac {- (- 2) \pm \sqrt {(- 2) ^ 2-4 (3) (5)}} {2 (3)}\\x = \frac {2 \pm \sqrt {4-60}} {6}\\x = \frac {2 \pm \sqrt {-56}} {6}

By definition we have to:

i ^ 2 = -1\\x = \frac {2 \pm \sqrt {56i ^ 2}} {6}\\x = \frac {2 \pm i \sqrt {56}} {6}\\x = \frac {2 \pm i \sqrt {2 ^ 2 * 14}} {6}\\x = \frac {2 \pm 2i \sqrt {14}} {6}\\x = \frac {1 \pm i \sqrt {14}} {3}

We have two complex roots:

x_ {1} = \frac {1+ i \sqrt {14}} {3}\\x_ {2} = \frac {1- i \sqrt {14}} {3}

Answer:

x_ {1} = \frac {1+ i \sqrt {14}} {3}\\x_ {2} = \frac {1- i \sqrt {14}} {3}

4 0
3 years ago
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