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Gnesinka [82]
3 years ago
9

Factorize the following (x+3)²(2x-3)​

Mathematics
2 answers:
aleksandr82 [10.1K]3 years ago
8 0
It would just be (x+3)(x+3)(2x-3)
prohojiy [21]3 years ago
5 0

Answer:

Step-by-step explanation:

it is already in factors.

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Romashka-Z-Leto [24]

Answer:

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8 0
3 years ago
Evaluate. 9^2 • ( 1/3) ^2 - 9 A) 1/9 B) 0 C) 1 D) 9 if right brainest
anzhelika [568]

Answer:

0

Step-by-step explanation:

9^2 * (1/3)^2 -9

PEMDAS says powers first

81 * 1/9 -9

Then multiply

9 -9

Then subtract

0

6 0
3 years ago
Each wheel on a car has a diameter of 22 inches.
ch4aika [34]
I think it will be 69.08
3 0
3 years ago
I need help finding the first five terms of the following explicit formula and the sequence
Katarina [22]

Answer:

Step-by-step explanation:

Explicit formula of the sequence,

A_n=59+11n

A_1=59+11(1)

A_1=70

A_2=59+11(2)

A_2=81

A_3=59+11(3)

A_3=92

A_4=59+11(4)

A_4=103

A_5=59+11(5)

A_5=114

8 0
3 years ago
Use the given minimum and maximum data​ entries, and the number of​ classes, to find the class​ width, the lower class​ limits,
Gennadij [26K]

Using proportions and the information given, it is found that:

  • The class width is of 14.375.
  • The lower class limits are: {19, 33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625}.
  • The upper class limits are: {33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625, 134}.

-------------------------

  • Minimum value is 19.
  • Maximum value is of 134.
  • There are 8 classes.
  • The classes are all of equal width, thus the width is of:

W = \frac{134 - 19}{8} = 14.375

-------------------------

The intervals will be of:

19 - 33.375

33.375 - 47.750

47.750 - 62.125

62.125 - 76.500

76.500 - 90.875

90.875 - 105.250

105.250 - 119.625

119.625 - 134.

  • The lower class limits are: {19, 33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625}.
  • The upper class limits are: {33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625, 134}.

A similar problem is given at brainly.com/question/16631975

6 0
3 years ago
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