let
(hypotenuse ) c = 10 in
(perpendicular) a = 8 in
(base) b =?
By using Pythagoras theorem
c^2= a^2+b^2
(10)^2 = (8)^2 +(b)^2
100 = 64 +(b)^2
100- 64 = (b)^2
36 = (b)^2
√36 = b
6 = b
hence b= 6 in
Answer:
SA=571.77
Step-by-step explanation:
SA==2πrh+2πr2=2·π·7·6+2·π·72≈571.76986
pls mark brainliest
Answer:
The range includes all numbers from 5 to 12.5.
Step-by-step explanation:
The range is along y- axis and the domain is along x- axis.
Range is given in heights and domain is given in time seconds.
It can depicted that for t= 0 secs the ball is at 5 feet and so on .
Therefore the range is given by numbers from 5 to 12.5.
Whereas the domain is given by numbers 0 t0 8.5 seconds
Answer:
For A.) there are only 2 so 2/8 would become0.25
B.) 4 even number 4/8= 1/2 = 0.50
C.) 1 Red 1/8= 0.125
D.) 5 Not blue 5/8 = 0.625
E.)3 Blues 3/8= 0.375
F.) 0 because there are no 9 so it's not possible
Step-by-step explanation: