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SOVA2 [1]
3 years ago
5

Use the given minimum and maximum data​ entries, and the number of​ classes, to find the class​ width, the lower class​ limits,

and the upper class limits.
minimum​, 19 maximum​, 134,8 classes
Mathematics
1 answer:
Gennadij [26K]3 years ago
6 0

Using proportions and the information given, it is found that:

  • The class width is of 14.375.
  • The lower class limits are: {19, 33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625}.
  • The upper class limits are: {33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625, 134}.

-------------------------

  • Minimum value is 19.
  • Maximum value is of 134.
  • There are 8 classes.
  • The classes are all of equal width, thus the width is of:

W = \frac{134 - 19}{8} = 14.375

-------------------------

The intervals will be of:

19 - 33.375

33.375 - 47.750

47.750 - 62.125

62.125 - 76.500

76.500 - 90.875

90.875 - 105.250

105.250 - 119.625

119.625 - 134.

  • The lower class limits are: {19, 33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625}.
  • The upper class limits are: {33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625, 134}.

A similar problem is given at brainly.com/question/16631975

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About 19​% of the population of a large country is hopelessly romantic. If two people are randomly​ selected, what is the probab
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3.61% probability that both are hopelessly romantic​.

34.39% probability at least one is hopelessly romantic

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they are hopelessly romantic, or they are not. The probability of a person being hopelessly romantic is independent from other people. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

19​% of the population of a large country is hopelessly romantic.

This means that p = 0.19

Two people are randomly​ selected

This means that n = 2

What is the probability both are hopelessly romantic​?

This is P(X = 2). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,2}.(0.19)^{2}.(0.81)^{0} = 0.0361

3.61% probability that both are hopelessly romantic​.

What is the probability at least one is hopelessly romantic​?

P(X \geq 1) = P(X = 1) + P(X = 2)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{2,1}.(0.19)^{1}.(0.81)^{1} = 0.3078

P(X = 2) = C_{2,2}.(0.19)^{2}.(0.81)^{0} = 0.0361

P(X \geq 1) = P(X = 1) + P(X = 2) = 0.3078 + 0.0361 = 0.3439

34.39% probability at least one is hopelessly romantic

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