Use the given minimum and maximum data entries, and the number of classes, to find the class width, the lower class limits,
and the upper class limits.
minimum, 19 maximum, 134,8 classes
1 answer:
Using proportions and the information given, it is found that:
- The class width is of 14.375.
- The lower class limits are: {19, 33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625}.
- The upper class limits are: {33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625, 134}.
-------------------------
- Minimum value is 19.
- Maximum value is of 134.
- There are 8 classes.
- The classes are all of equal width, thus the width is of:

-------------------------
The intervals will be of:
19 - 33.375
33.375 - 47.750
47.750 - 62.125
62.125 - 76.500
76.500 - 90.875
90.875 - 105.250
105.250 - 119.625
119.625 - 134.
- The lower class limits are: {19, 33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625}.
- The upper class limits are: {33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625, 134}.
A similar problem is given at brainly.com/question/16631975
You might be interested in
Answer:
A. The first 2 are equivalent expressions.
B. The last 2 are equavalent expressions.
Answer:
n = 7/2
Step-by-step explanation:
4n^2-22=27
4n^2 = 27 + 22
4n^2/4 = 49/4
sqrtn^2 = sqrt(49/4)
n = 7/2
-5 - (-7) = -5 + 7 (Answer D)
51 3/4 cubic yards is the answer