<img src="https://tex.z-dn.net/?f=sec2x-1%3D0" id="TexFormula1" title="sec2x-1=0" alt="sec2x-1=0" align="absmiddle" class="latex

$\frac{1}{6}d+\frac{2}{3}=\frac{1}{4}(d-2) \\ \\ \frac{d}{6}^{(2}}+\frac{2}{3}^{(4}=\frac{d-2}{4}^{(3} \\ \\ 2d+8=3(d-2) \\ \\ 2d+8=3d-6 \\ \\ 2d-3d=-6-8 \\ \\ -d=-14 \\ \\ \boxed{d=14}$

4 0

3 years ago

Needs to be graphed and solved please help

il63 [147K]

Answer: here it is graphed and it cant be solved because there are no solutions as seen on the graph!

Step-by-step explanation: hope i helped please mark brainliest!

7 0

3 years ago

Here at Karen University we offer the finest education! From language lessons, now repeat after me “I want to speak to the manag

GaryK [48]

Answer:okkk

Step-by-step explanation:

3 0

2 years ago

What is the area of the polygon shown below? (in the image). A. 322 mm^2 B. 364 mm^2 C. 520 mm^2 D. 584 mm^2 Show all work pleas

GalinKa [24]

Answer:

A. 322 mm^2

Step-by-step explanation:

First split the shape into two (a rectangle and a triangle).

Then calculate the area of those shapes.

Rectangle: 20 x 14 = 280 mm^2

Triangle: 6 x 14 / 2 = 42 mm^2

Add them together.

280 + 42 = 322 mm^2

3 0

3 years ago

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